2022年徐州市高考化学全真模拟密押卷含解析

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ஹஹᓴஹஹஹஹஹஹஹ(⌕8)⚪⌕⚪⌕!஺4ஹDூ᪆௃A.ᙠ᪗%&'()*ᵬ,ᕈ.᝱01ᵨ34᥅64789:;A┯=>B.?@AB@ḄᨬEFCH2,ᨬEFḄFG14,?@AB@ḄHᡂḄ42gJᔠ34LᨵᨬEFḄᱥOḄG3mol,ᡠQᐸLCᦪT3NA,B┯=>C.ᵬ⏣VWḄXYFT2cH3OH+3O2Z[2co2+4H2O,᪷]XYF^_`2moiᵬ⏣aᐰVWcd12moiᵯᑣImolᵬ⏣aᐰVWgᡂCO2AH2O,cdḄᵯᦪhT6NA,C┯=>D.᪷]ᵯ₹jឤ^_n(Na+)+n(H+)=n(OH-)+n(CH3co6),ᵫmn.oLឋᑣn(H+)=n(OIT),ᡠQn(Na+)=n(CHCOO),qrsImolCHjCOONanmtu⏚Ln.ᕈLឋn.LCH3co஺-ᦪhmNA,Dxy>3ᦑᔠᳮ⌱⚗Do5,Aூ᪆௃XஹYஹZஹQஹRT~ᦪᜧḄᕜᐗRᨬ᜜ḄᵯᦪQᨬ᜜ᵯᦪḄ4ᑣQᜐmIARᜐmWARXᨬ᜜ᵯᦪ)ὅRḄᜧᦑXTCᐗஹRTSiᐗ>ᨬ᜜ᵯᦪZ>Y>4,)ὅmᦑYஹZᜐm)ᕜZᡂZ?ᦑZTOᐗᑣYTNᐗ>Q᪶᜜ᵯ᣸02-QᜐmIAᦑDTNa,]r89஺ூ௃᪷]¡ᑖ᪆^_XCᐗYNᐗZOᐗRSiᐗQNaᐗ஺A.ᓄᔠᱥXZ2CCh,¥ᱥOᐳ§ᓄᔠᱥᵫᑖ᪀ᡂᑖLᨵᐳ§A┯=>B.ᙠ¡©ªᐗLᨵQ⊤¬ḄNaᐗ®ᐗqr©ªᐗLQḄ®ឋᨬ¯Bxy>

12C.ᐗḄ±®ឋ²¯ᐸEᓫ´ᓄᱥḄµ¶ឋ·²¯஺ᵫmᐗḄ±®ឋN>C,ᡠQ´ᓄᱥḄµ¶ឋNH3>CH4,Cxy>D.ᐗḄ±®ឋ²¯ᐸᨬ¹§ᓄᱥº»Ḅ¼ᓄᱥḄ⏚ឋ·²¯஺ᵫmᐗḄ±®ឋN>Si,ᡠQ⏚ឋ`HNO3>HSiO,Dxy>23ᦑᔠᳮ⌱⚗A஺ூ¾¿௃⚪ὃÂÃᐗᕜ⊤ᐗᕜÄḄ»ᵨḄ_Å஺᪷]ᐗḄÆ᪀ÇÈᐵÊ89ᐗËÌ⚪ḄᐵÍÎ〉L஺6ஹDூ᪆௃A.c(Cl")=0.100molLTḄn.LḄᱥᧇjឤc(Cr)=c(HS-)+c(H2S)+c(S2-)=Ñc(Na+)=(U00molL-i,ᵯ₹jឤ2c(Cl-)+c(HS)+2c(S2-)+c(OH)=c(H+)+c(Na+),ᑣc(OH)-c(H+)=c(HS)-c(S2-),ᦑA┯=>2B.ÒᐭHC134ÔS2-¼ÕÖn.ᕈ×ឋᐸ¼YÎ¥ᨵØÙ¼ÚgᡂOH-,ᡠQÛᙠc(S*)>c(OH)>c(HS)>c(H+),ᦑB┯=`C.n.LḄᵯ₹jឤTc(Cl-)+C(HS-)+2C(S2-)+C(OH)=C(H+)+c(Na+),ᱥᧇjឤc(S*)+c(HSj+c(HS)=-22c(Na+)=0.100mol«L',ᑣc(Cl)+c(OH')=c(H+)+c(HS)+2c(HS),ᓽc(Cl')+c(OH-)+c(S2')=c(H+)+c(HS')+c(S2-)+2c(HS),22ᙠc(HS)=c(S2)×ឋn.Lc(OH)>c(H+),ᡠQc(Cl)+c(HS)D.n.LḄᵯ₹jឤTc(CD+C(HS-)+2C(S2')+C(OH-)=C(H+)+c(Na+),n.ḄpH=7,ᑣn.Lc(OlT)=c(H+),c(Na+)=c(Cl-)+c(HS')+2c(S2-),n.LÛᙠᱥᧇjឤc(Na+)=2c(H2s)+2c(S=)+2c(HS-),ᡠQÛᙠc(Cr)=c(HS-)+2c(HzS),ᦑDxy>ᦑᫀ⌱Do7ஹBூ᪆௃ᓄÞß»ᨵḄàᨵḄ᠒ᑣ1ᵨᓄÞß»â᳛ᩭ¶G⊤¬ᓄÞß»89Ḅà᠒ᦑAxy>^⌮ß»æᑮᓄÞè⊝&᝱êx⌮ß»â᳛ëß»ìíᨵîï,B⚗┯=>ñòᓄÞß»â᳛Ḅ⌕qß»ᱥóḄឋOC⚗xy>ᓽᓫô47ᑁḄß»ᱥᑖö,ᐸLG¹Ḅ÷ᓄᑖᦪøêö,ᑖÔùúûḄüýö,ß»â᳛þàᓣ

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18(2)ᓄᔠᱥSi3N4/tᨵḄᓄ}I`ᐳHI(3)SiCh^NaOH.WXḄ~SiO2+2OH-=SiO32+HOo224ஹWX1ᡂWXᓄᑺ2cH3CHO+O2᦮”>2cH3COOH•fCHj-CH%nCH3coOCH=CH2᯿ṕ_>(:14HCOOCHCH=CH>HCOOCH=CHCH^HCOOC(CH3)2230C=CH2ூ^᪆௃TᓄSᑮ⏣ᙽTWXSᑮ⏣⏣#x4ᡂ¡¢BCᓄᓄ£SᑮḄ⏚⏚3¤ᙠxᩩ§¨1ᡂSᑮCH3coOCH=CH2,ᓽᱥ7D,ªDᙠᓄᑺḄᵨ¨ᙠ¬CH%uw1WXSᑮECHᔆC—1ETᵬ⏣°±ᣚWX³´WXᙠ⚪µ¶·/¸¹º»஺¼ᩭ¾¨☢0C6H6ÀÀ3ÁWXSᑮÂÁÀᓽᱥ7F,ÂÁÀ3CLSᑮM,ÃÄWXঠḄÆÀÇÈḄU¡¢⌕ᙠḄᓄ¨ª#Æᐝ᯿¨஺ூË^௃(1)WXঞÆ°±ᣚWXÍ▭ÈÏᔠWXḄᱯÑWXটÆ´1ᡂWX³ÓuwÔWXᱥ3ᡂᱥḄᑖ~ᩭ¾»ªWXঠÆᙠḄᓄ¨ÕÖḄ(2)BᡂCᓽḄᓄᓄ~2cH3CHO+O2Tg->2CH3COOH,ªWXঝ1WX~•FC%—CHØnCHCOOCH=CHÙ⁐ᑺ_>Ú»ߟC—C;320(3)!ÜÝÆᙠÞᡃàáâᨵãgáâᐳᨵ4g¡¢RÓᨵ4g(4){äWXᨵâåÆC4H6஺2/æᨵ2´5◀°â᜜#u¼ᨵé᜜Ḅâ¡¢æÆᵬ⏚°Ïᔠᩩ§Ḅê᪀ᨵHCOOCHCH=CH>HCOOCH=CHCH,HCOOC(CH3)C=CH«2232ூìí௃îᩭᐝ᯿ᩩ§¨ḄÆᵫâWX4ÀÇïðÈḄUஹñâÈḄUò᝞3'ôõᙠᐝ᯿¨#41ᡂª4ö}à÷£¾ᑮᐝ᯿³´ᩩ§x⌕ÃÄ஺25ஹᑖ.øᧅeghbafú⏚µûôü■þÿ
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19ᢵ⏒ᓄᜧᱥḄ☢!"#$᳛COCI2+4NH3H2O=CO(NH)+2NH4C122+4HO79.3%2ூ'᪆௃প+,-./ᘤMḄ12஺(2)᪷567⏒89:;⌕=>?@A☢Bᱥ⌕◞D9EF-.GH஺(3)᪷567IJ⏒KLM9:;᦮OP᛻⌕=>ᦑ-ᑮTᫀ஺(4)᪷5(2)-ᑮVWXᮞḄZᵨ\=>]஺(5)᪷5⏒(COCL)^_`ᵬ᧕ᢵ-.bcdeᳫgḄZᵨ\ᜧᱥḄ☢!"#$᳛஺n(6)⏒hijᵨkl9ᔾᦈoᡂqrsᓄtFᑏ.vwxᐜ᪷5vwxz{|▭~ὑᵬ⏚ḄFz{ᓄ᳛஺ூ'௃(1)/ᘤMḄ12\ᑖᧅᦑTᫀᑖᧅ஺(2)᪷567⏒89:;⌕=>?@A☢Bᱥ⌕◞D9E:;X⌕ᵨk⏚=>ᢥᵫḄGHe—>cߟ>d—>g—>h—>b—>aߟ>f,ᦑTᫀeghbaf«(3)᪷5⚪-.ᑺX\k⏚ᦑTᫀk⏚஺(4)᪷5(2)-ᑮVWXᮞḄZᵨ\=>]■9E
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ᐭ஺ম⏒(COCL)^_`ᵬ᧕ᢵ:;9ᔠᱥḄZᵨ\■ᵬᢵ⏒ᓄdeᳫgḄZᵨ\ᜧᱥḄ☢!"#$᳛ᦑTᫀ■ᵬᢵ⏒ᓄᜧᱥḄ☢!"#$᳛஺II(6)⏒hijᵨkl9ᔾᦈoᡂqrsᓄ᪶ḄᓄvwxCOCI2+4NH3H2O=CO(NH2)2+2NHC14+4H2O,COOH00Q+COCh->d+CO2+HCI121g140.5gxg562g121gxg=140.5g562g'-x=484g

20a=^?l^xl0°%=79.3%,ᦑÖᫀF\COC12+4NHyH2O=CO(NH2)2+2NH4C1+4H2஺479.3%஺610g26ஹ⛳VNaHCChz{ḄþOÿ
H2s஺4ḄNaOHᵨC(hᘤḄᐭE250mL5.4g〉⁐ᔣᐸ!ᐭ"KSCN#$⊈&⁐ᑣ()Ꮇ+2,-2Fe?++Br2=2Fe3++2Br-4Fe2++2Br+3C12=4Fe3++Br+6Cl2ூ᪆௃I../Aᵨ0⏚┛34⏚ᑴ67ᓄ0./B9ᨵḄNaHCCh⛳3ᵨ<◀>67ᓄ0Ḅ?ᓄ@A./C9ᨵḄ
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H2s04ḄgNaOHg(2)ᐜᐭ~CCh,ᘤḄḄ7C᡾|}g⌕ᐭCO2,iFG!HḄ./DᐭE¡MN¢ᐙᑖᦑᫀpᵨCChᘤḄ_ᐭEg(3)¥ᑴ200mLO.lmol/LFeBoḄ¦ᴻ¨ᘤᨵ©ªஹ«ஹ¬ᜮrஹ¦ᴻ®3250mLg250mLO.lmol/LFeBnFeBrḄᱥḄp0.25mol,ᑣFeBrḄp0.25molX216g/mol=5.4g,ᦑᫀp250mL;5.4g22(4)#Ꮇ+2,-ᔣFeBnr!"sᑴḄ?tFe?+±CL7ᓄᡂFe3+,ᔣ²Ḅ⁐!ᐭKSCN³$p&⁐ᦑᫀp〉⁐ᔣᐸ!ᐭ"KSCN#$⊈&⁐ᑣ()Ꮇ+2,-g(5)Fe2+3BnO7ᓄijOᡂFe3+3BF,Ḅ´µ¶·p2Fe2++Brz=2Fe3++2Bi-,ᑣᦑᫀp2Fe2++Br=2Fe3++2Brg2(6)40mLO.lmol/LFeBnFeBnḄᱥḄp0.004mol,0.004molFe?+¸ὑCLḄᱥḄp0.002mol,3x103molCLᨵ0.001molCLM¸ὑBi-ḄᱥḄp0.002mol,ºMḄFe2\Br,3ClḄᱥḄ2¼p0.004mol0.002mol0.003mol=4:2:3,ᑣḄ´µ¶·p4Fe2++2Br+3cl2=4Fe3++Br2+6CT,ᦑᫀp4Fe2++2Br+3C12=4Fe3++Br+6Cl-.2

21ூ_௃¡⚪ὃ£|¤vᫀḄ¥z8¦§s¨©|¤⚪7ª_«dஹᔠឋ«¯ᐙᑖὃ£ᑖ᪆ஹᳮ'L²³ᮣµᵨ¶Ạ7ªḄL²¸¹º»ᓄ|¤¶¡¼Zv½¾¿ÀMᱥḄឋ³ᓄ|¤vᫀ¥zÁᑣ\'TᐵÄ஺27ஹÅÆÇᜐᳮFeOABCD23ூ'᪆௃(1)ᒕÊḄ]KLᜐᳮÅÆÇᜐᳮ(2)ᵫ,3ḄËᓄᩭ'TFe2(hFe3()4FeOFeËᓄ3Í(3)|¤ÎÏÐ᣸ÒḄÓÔ"ÕAÖ×ØᨵÚᶇḄÜ?ᓄÝÞßᐭCO,ijàᐸâᑮBãä|¤åæL■᎔ᔾèூ'௃(1)é?ᓄᨵêKL᣸ëᦈìᡈᔾᦈî|¤ïᙠéO¾ñÅ◍\ÅÆÇᜐᳮ(2)FezO3sCO\óôõᓣ÷ø⌲ú
ûḄᐜoᡂFejCh,FoᡂFeO(ý⁐)ᨬᡂFe,ᵫᑁḄᓄ3᝞ᨵFeO4,Fe3O4FeOFeᓄ2᝞FezChᑣFezChFe3(h3FeOFeᓄ3ᦑᨵᩖ"FezOj(3)CO◀$"%&ᱥ᜜A.ᑭᵨ+,ᓄ-.ᙠ01234᣸6789Ḅ:.■<=>4?ᰦAᦑABCDB.+,ᓄ-EFGH■OPQCO.ᙠ+,ᓄ-.9RE᧕T,ᓄ■<ᡂᱥT,ᓄᦑCBCDD.UVḄCO2ᐰXYᐭ78b9Z[01\]^_01Ḅ`CaᦑDBCDᦑ⌱ABCDூde௃gdMᙠGhiQᐭCORḄ,ᓄᱥḄjᓄklmnᓄḄopdqrs⚪Ḅuẚw஺28ஹ””III0.{|ᕜ~{WBTiCh"ᨔTiCLTiBn"ᑖᨔᦑTiChḄᰚd_TiCh3d4sTiBmḄ᪀TiBnḄᑖḄTiCLᑖᜧᑣTiBnḄTiCLḄᦑTiBmḄᰚdTiCLḄᰚd_sp?ᩖᓄspᩖᓄ☢1:1648x2+16x4---------xlOa-bc-NAூq᪆௃(1)TiḄᦪ22,ᙠᐗᕜ~⊤9G{|ᕜ~{WB¡᝱TiḄ£¤ᵯ᣸¦"

22PhiIIIN.g3d4s(2)§o¨ᨔḄᰚdᨔḄᰚd_ᑖᨔḄ᪀4ᑖ©ᜧ©ᰚd©_D(3)ᑭᵨ£¤ᵯᦪªᩖᓄ«¬ᑖ®Ḅ:®᪀¬D(4)ᨔ¯9pᦪḄª°D(5)ªTiChᨔ±a4²³+pᨔ¯9ᨵ2pTiஹ4pO²³ᨔ¯´ᦪḄᓫᣚ·஺ூ¸q௃(1)TiḄᦪ22,ᙠᐗᕜ~⊤9G{|ᕜ~{WB¡᝱Ti᪶᜜ᵯ᣸¦º"Ai*3d24s2,¡᝱TiḄ£¤ᵯ᣸¦"Bw»¼0.D3d4s(2)TiCh"ᨔTiCLTiBm"ᑖᨔᦑTiChḄᰚd_TiCLTiBnḄ᪀TiBnḄᑖḄTiCLᑖᜧᑣTiBmḄTiCLḄᦑTiBnḄᰚdTiCLḄᰚd_D(3)COCLᑖ9-Ḅ£¤ᵯᦪ3,ᦑCOCLᑖ9-Ḅᩖᓄ¾º"sp?ᩖᓄ¿9À-ÁᨵÂᵯCOCLḄ:®᪀¬☢DCO2ᑖ9-Ḅ£¤ᵯᦪ2,ᦑCO2ᑖ9-Ḅᩖᓄ¾º"spᩖᓄD(4)ÃÄᔠᨔÆ®ᵫÇᡂḄᨔ+¨ÃÄᔠᐹᨵ☢Àɾᨬ±ᚮËḄ᪀ᙠᨔ¯9TiG⚔d☢À8A1GÍÀÀᦑᙠ+pᨔ¯9Tipᦪ"M8xl+6xl=4,AlḄpo2ᦪ"12X'+1=4,Îᔠ9TiAlḄᦪÆ":4:4=1:14(5)জÐ"TiOᨔ¯9Ti4+G02-ᡠ᪀ᡂḄBÓ☢ḄÀᡠTiOᨔ9Ti4+ḄÔᦪ622ঝ᪷×ᨔ¯ØTi8pᙠ⚔dஹ+pᙠÀO4pᙠ☢Àஹ2pᙠÀᦑÎᨔ¯9Tipᦪ"8x1+1=2,OḄpᦪ"4xÙ+2=4,(ax10஺)x(bx10஽)x(cxio'x᜛XNÝ48X2+16Þ4,8248x2+16x4IßP=;—x10-g«cm3oabc•N
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23XCH2=CH2o-OHCCH2cHeH2cH2CHO--------------------►HOOCCHCHCHCHCOOH222ÎḘÐᓄᑺஹÒ/CH3ூq᪆௃×⚪9ᔜᱥḄjᓄᐵõØ,Ḅᓄᑖ÷MᙠøùḄú?=ᡂ%&ûᐭ+püý¡(ÿ)ᯠḄᡂBḄ᪀J,ᯠC⏣!"#ᓄᡂ%ᓽ'ᑮD,)⚪஺ூ-.௃Ó᪷⚪ᔜᱥ3Ḅ4ᓄᐵ67ᵫᑮCḄᓄᑖ:;<ᙠ>Ḅ?@ᡂABCᐭEFGH(J)ᯠḄᡂBḄ᪀:ᯠC⏣!"#ᓄᡂ%ᓽ'ᑮDOপMF.!tᨵeGuvᑣxᔠᩩlḄBḄzᑖ{᪀|}ᨵ-OH~-C4H9,ஹஹ?@ᐵ6ᐸ-C4H9ᨵ4᪀ᡠᐳᨵ12᪀◀B᜜ᨵ11a(4)DḄᑖ

24᪀ᓽᑏ~CH2=CH2ᧇᑴᜓᨵᱥᐜᵨ>b£ᡂABᡂ?bUHOOCCHCHCHCHCOOH222>?b>ᡂᡂ?b⏣?b⏣¤ᡂ3.b£3.b£#ᓄᡂ¥ᱥᦑ¦?H_OHOHj<>஺OficaijCHCHjCHjaiO——►HOOCCH]CHOi]CHCOOH3CH>CH>CHjCHூ¨©௃ὃ«Ḅ;ᨵ~ᨵᱥᔠᡂ¬7®¨¯°ᨵF±Ḅ²ᔠឋ´µ¶.⚪Ḅᐵ·ᙠ¸ᐙᑖᑭᵨ⚪»¼~Ạ7®¾ᔠᮣÀᙢBᵨᑮᨵᔠᡂ.