2023年新疆哈密石油高考数学全真模拟密押卷含解析

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2023
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16(1)v0ᦪᑡÉ40“"পᦪᑡ”=ᡠzS,=%+1-1,ᦑS“_|=஺"ul(n>2),´LW஺ᵨ=2a“,(nN2),ᙠS“=஺”+|-1ÒÓ஻=1,ᑣW%=2,ᦑ%=2%ᡠz£i!!L=2,(/1eN',n>1),anᡠzᦪᑡÉ4×z10✌⚗=z20½ºḄºᦪᑡ=ᡠz%=2"Çv0S,,=%+Ù1,ᡠzS“=2"-1.(2)ᵫ⚪hWS“=a,.-2,ᦑS,i=%+i-2(n>2),´LW4+2=+%=(nN2)ᡠz=[=ᙠ2\=ᖐuaa="3-%(஺Ã+%)=a(a-a„)-a,,2nn+2n+ln+lOv0q,+i-=a஻T=(nN3)ᡠz[஻23\,-aa=«„(«„-«„)-<=ajnn+2+1+|ᡠz,"+i--஺"+◍"-11=(n23)ᡂ<=ᡠz[஻23\=ᦪᑡÉ,Çu+£i|×Ëᦪᑡ=ᡠz|a4-|=|o32-aa|,(n>3)24v0[஻=2\,Ü=«„i+aᡂ<,+nᡠz஺4=%+¾=ᡠz|Çu%*|%|=|%2-0a3-%21,(n23)2ᙠS“=4+2-2ÒÓ஻=1,v04=1,ᡠzW4=3=ᡠz|9—3஺2-Ì2|440,ᵫ஻=2\$ᵫ0᦮ᦪ,

17W=0,±1,±2,±3,±4,±5,±6,Ý=0,±1,±2,±3,±4,±5,±6ᑖßàᐭ|9-3ÌuqI<4()W,Ì=0,±L±2,±3,±4,±5,-6,ᡠz¨ᙠᦪᑡÉ%Ñᔠ⚪h,âḄᡠᨵZ0Ì=°=±1=±2,±3,+4,±5,-6.ூ)௃⚪ὃᦪᑡḄãäஹºᦪᑡḄ»⚗½æᦪᑡ⌴ç½Ḅèᵨ;ὃèêT^ஹëìçᳮT^æîãäḄᳮT^;»ïðñᑭᵨ⌴ç½=Wᑮᦪᑡ0Ëᦪᑡ×⚪Ḅᐵò;¥¦óᔠôõஹ§öᜧôø⚪.(4ஹI—Ù4120.(1)f—=3+A/3(2)f(x)Ḅ⌴Lùú0—æᐔ512J|_12_ூ᪆௃7F(1)ᓄý@ᦪ/(X),àᐭX=—,þêᓽi12ᐔ(2)ᐜᑭᵨᦪḄឋᦪḄᓫ⌴ᔠXGᓽ.ூ!௃(1)f(x)-6cos2x-x/Jsin2x=3(1+cos2x)~Gsinlx=->/3sin2x+3cos2x+3=—2Gsin(2x-]J+3,89/:=3+6.JTTT7T(2)+2kᐔW2x—+2kᐔ,keZ232ᐔ57r!>?■?+k7TxeIᨵ?TT12

18541\TCᦑy(x)Ḅ⌴YZ[—B\:^,ூ_௃`⚪a⌕ὃd3/eᦪḄឤ&fghᦪḄijkឋmnoC᫏⚪.21.(1)x=l,V=|Z(2)^(2-x),cosZEMF=0,ᑏ/e☢w,X-#ᐸ}ᦪḄᨬ7ᑣᫀ>#.ூ;௃(1)ᵫ⚪LAEF8&Ὺe/e!AE=CF=x,.-.BE=BF=2-x(0$0,$xw(&-1,2)=r(x)<0,¤<¥=⌲-1=SAEMFᨵᨬᜧ7.ᵫ(1)?}☢EA/E,

19/s┵uwḄᨬᜧ7V=gS.MD,E=2.4EWf¤$cosC=´{᪷¶¤°eḄ·h¸cos8ᓽ>5(2)ᵫy?>$º=4¢ᑭᵨ·h²ᳮ“ᵫy?¸COksinC,{᪷¶/eḄ☢w#¼½ᓽ>.ூ
௃(1)B=2C,¤sinB=sin2C=2sinCcosC,,ryJᙠgA8CCᵫgh²ᳮ$¾@¤?smCcÀNb=4c.-sinBb2A/5•cosC=--------=—=------2sinC2c53cosB-cos2C=2cos7-C-l,5(2)c=59\[5b—4c9*,•஻=46,ᵫ·h²ᳮ$b2=a2+c2-2accosB,ᑣ80=/+25-2஺-5'(,ᓄÂ$஺2@6஺-55=0$஺=11ᡈ஺=@5(Ã7ÄÅ),BD-6,CD—59

20cosC=———>Cei0,»,sinC=>/l-cos2C=,A4£>CḄ☢wS=LoCAC-sinC=Lx5x4V^x^=10.225ூ_௃`⚪ὃd3/e☢wQ±gh²ᳮஹ·h²ᳮḄᵨὃd3¤°eḄᵨὃd3ƪ«noÇẠ⚪.