2023年四川省三台高考数学全真模拟密押卷含解析

《2023年四川省三台高考数学全真模拟密押卷含解析》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

2023
ὃᦪᔁ
⚗1.ᔁὃḄஹὃஹὃᑏᙠ!⚪ᔁ⚪ᓱ$஺ᵨ2B)*!ᔁ+,-B./ᙠ⚪ᓱ012$஺ᩩ4ṹ67ᙠ⚪ᓱ8$9஻ᩩ4ṹ67ᜐ஻o2.=⌱?⚪@⌱ABC⚪ᫀEᵨ2B)*F⚪ᓱ$G1⚪H⌱⚗ḄᫀIJK/LM᝞◤ᦋQᵨRSTUVEW⌱/ᐸYᫀ஺ᫀZ[ᙠ!⚪ᔁ$஺3,^⌱?⚪_ᵨL⁐abḄc*ᡈea*=ᫀ_ᑏᙠ⚪ᓱᔜ⚪Hᢣhijᑁ012$M᝞◤ᦋQᐜᑜᣵoᩭḄᫀᯠEWᑏ$rᫀMZsᵨ)*/ᦋt஺Zᢥv$⌕x=yᦔ஺4.ὃ_|⚪ᓱḄ᦮~஺ὃ!E!ᔁ⚪ᓱ஺ஹ⌱?⚪⚪ᐳ12C⚪BC⚪5ᑖᐳ60ᑖ஺ᙠBC⚪AḄ⌱⚗ᨵ⚗ᔠ⚪H⌕xḄ஺1.KA,B,CZᐳᑣ"-|=|-.A.ᐙᑖZ⌕ᩩ¡B.⌕Zᐙᑖᩩ¡C.ᐙᑖ⌕ᩩ¡D.£Zᐙᑖ¤Z⌕ᩩ¡2.¥¦ᔠA={-x,y.,+/<16}¦ᔠB={-x,y\x+y<4,x>0,y>0}⊤¯Ḅ°☢ijᑖ²Q5´ᙠij5ᑁµ¶Kᑣ·K¸ᙠij஺2Ḅᭆ᳛»-.1117T-2A.—B.-C.--D.----4஻712¾4஻3.¿஻ÀᩩZÁḄÂa,£ÀZÁḄ°☢ÅᑡÇ⚪ÈÉḄ-.A.a1/3,mua,nu0,ᑣB.´᪷ua,ᑣ/”஻஻C.aua,஻uÍᑣa_L£D.´஻?_La,mlIn,nll/3,ᑣaJ■ᑖ4.ÓÔ¦ᔠÕ=-HÖ<08={-1,0,1},ᑣACI8ÙÚ-.A.{^-10o6.ÓÔëᦪ/-%.=I2cCòóᨵZÁḄ᪷¥ᨬᜧḄ᪷Ḅᡠᨵ¶ê»¦ᔠᑣ“ëX2+2X+2,X<0

1ᦪ÷-x.=/-x.-øxe஺.ᨵÀúK%ûM”Ḅ-..A.ᐙᑖZ⌕ᩩ¡B.⌕Zᐙᑖᩩ¡C.ᐙ⌕ᩩ¡D.£ZᐙᑖüZ⌕ᩩ¡7.ÓÔᦪᑡþ4ÿ
"3஺Ḅᦪᑡ4%ᡂᦪᑡᑣ=A.4B.3C.2D.1vrcqXTC8.ᦪ/=!"ᙠ$%,ᑐ(Ḅ)*ᜧ,2+2229.ᦪ/x=cos2xxw[-627Ḅ)*8ᦪgx=sinxḄ)*Ḅ<=>ᙶ᪗ḄAM

211.CDᦪEFGE=1+3HI|z=()z11.11.11.11.A.—+—lB.——+—zC.--------1D.---------122222222v+112.J=GjKLᵫNO,\=8-2|+/8*=3RᡂḄSTUVᑁ(ᒹZ[\)ᑣ0Ḅ^_R()x-2A.[-3,1]B.[-3,5]C.(-oo,-3]U[5,+oo)D(-oo,-3]^[1,+oo)Eஹbc⚪ef⚪ᐳ4h⚪ih⚪5ᑖᐳ20ᑖ஺13.ᦪ/(x)=cos2xḄᨬhlᕜn,ᓫp⌴rUs.14.tuvwᱥOCey=ᡭḄᯖ=vC($=M(-4,3),ᑣAPMFᕜ|Ḅᨬh_.15.ᙠUs[-6,2]ᑁ}~^$ᦪ%,ᑣ.%ាyᦪḄᭆ᳛.16.Cᦪf(x)=-3/+6xᙠUs,(Ḅ_V[-9,3],ᑣ$aḄ^_R.ஹ⚪eᐳ70ᑖ஺ᑏᦻஹᡈ஺17.(12ᑖ)tuᦪ/(x)=(x—a)/nx(aeR),Ḅᦪ/'(x).(1)aM/ஹ'(Ḅ¡=¢(2)a=0ef(x)1).(1)À¸»3ᔴḄ[▭ᡂf(ᓽ¼¸©$ÍsḄÁᡂfοÍs¸»Ḅᦪ)¢(2)ÏiÀ¼¸°ᙳᡂf2=៫,e<16¢X

33ᐭᢥᦪᑡ%=ᓫ:ᐗ⌴"#$%ᐭ60ᜩ#'(:)60ᜩḄ+ᢗᐭᜧ.-1ᔊ11ᐗ.20.12ᑖᙠজ஺=2,ঝa=b=2,ঞᓃ=c=2)78ᩩ:;<⌱8#⊡ᐙᙠ@☢B⚪;#'AAZ?஺Ḅ☢DḄEᡈᨬᜧE.HIAABCḄᑁKA,B,CᡠMḄNᑖOP஺#b,c,7N஺#b,cQ☢DSRSᐵUV:4S=b2+c2-a2,W_____________,'ØABCḄ☢DḄEᡈᨬᜧE.x-2+Icosa21.12ᑖᙠZ☢[Kᙶ᪗UxOy;#^_GḄ`ᦪabPீd.aP`ᦪ.eZ☢[Kᙶ᪗UḄfy-2smag஺P᩽g#xiḄjkliP᩽imn᩽ᙶ᪗U#[_C2Ḅ᩽ᙶ᪗abP°sin8=6.1'^_GḄ᩽ᙶ᪗abo2pGqGrgḄrgPA8,'A4O3Ḅ☢D.22.10ᑖpX,y,ZGR,zx+2y=m.1s2+2V+3z2ḄᨬtEP4,'ḄEo2X?+4ஹ+'z221,(vw/yீ1ᡈ᪷21.2`ὃ{ᫀஹ⌱}⚪w~⚪ᐳ12t⚪#t⚪5ᑖ#ᐳ60ᑖ஺ᙠt⚪Ḅ8⌱⚗;#ᨵ⚗ᔠ⚪⌕'Ḅ஺1.Cூ᪆௃ᑭᵨᔣᚖ[Ḅ⊤ஹᔣᦪDḄ#ᔠᐙᑖ⌕ᩩ:Ḅᑨᓽ.ூ௃ᵫ.gA,B,C¡ᐳ_#¢!|Afi+AC±fiC^A6+^C-fiC=0<»AB+AC-AC-Ae=AC2-AB2=0஺/?=¦¦§¨§o

4ᦑ"(ë+⊟)”“Iï=Iṹ”Ḅᐙᑖò⌕ᩩõ.ᦑ⌱eC.ூ=ø௃fh⚪ú⌕ὃüᐙᑖஹò⌕ᩩõḄᑨþὃüᔣᚖḄ⊤ὃᔣᦪḄẠ⚪.2.Cூ᪆௃⚪☢ᨵᐵḄ"#ᭆ᳛⌕'M)ᙠ+,ᑁḄᭆ᳛.⌕'Aஹ3ᡠ⊤+,Ḅ☢ᯠ45ᐭ+,Ḅ☢ᭆ᳛782=;ᓽ=>ᫀ.+,RḄ☢ூ@௃᪷⚪=BᔠA={(x,y)|/+16)ᡠ⊤Ḅ+,ᓽP᝞Rᡠ⊤:ḄᙊUᑁVḄW☢+,☢P16%,Bᔠ3={(x,y)|x+y-4,,0,%..0,%஺}⊤ḄW☢+,ᓽPR^ḄRtAAOB,5cᳮ=gx4x4=8,Q1᪷"#ᭆ᳛Ḅ;78=2=3=416%2gᦑ⌱jC.ூkl௃m⚪n⌕ὃo"#ᭆ᳛Ḅ;m⚪☢ᨵᐵḄ"#ᭆ᳛pq.rm⚪Ḅᐵs⌕tu'vw+,Ḅ☢.3.Dூ᪆௃x⚪ᑖ᪆je,{/q|a஻||£,|஺J■gᦑ⌱D.ὃkjk☢Ḅᐵ.4.Cூ᪆௃ᐜᓄBᔠA,Bᔠ8'B.

5ூ
௃©PA;ª(°x\-209¶vᦪf(x)=JÓḄR¸᝞R''x'+2x+2,x<0

6ᵫRD=(2,4],ᦪF(x)=f(x)-kx(xGD)ᨵ2Ø¿kᓽf(x)=kxᨵwØÙḄ᪷,ÚÛy=kxy=f(x)ᙠ(2,4]Áᨵ2ØkÜ!|kḄᨬ«£P1;ßàkḄy=10g2XḄᑗkP(x()âOg2Xo),Ä᳛PãjlxrtiriᑣᑗçèPy-iogx=--x0),2xln20¼(0,0)5ᐭ=—log,Xo=—êᓽx0=e,.•.ᑗÄ᳛Pëm2eln2(11ஹJkḄª£Æߟ5,12eln2JᦪF(x)=f(x)-kx(x€D)ᨵwØ¿k”“k>g”ḄᐙᑖÈ⌕ᩩÊ,ᦑ⌱A.ூkl௃m⚪n⌕ὃoᦪ¿kḄᑨËὃᦪ²ÀᓄðñçᦪòóᔠḄ⚪ðñçôõoᑭᵨÂᦪẆ÷ßøÁùkᜐḄᑗçèx⚪ᨵãËḄûᔠឋ^᫏⚪.7.Aூ᪆௃᪷þᦪᑡ
ᦪᑡᑮᫀ.ூ
௃ᵫ4%4ᡂ
ᦪᑡd=஺஺6,ᓽ(q+2d)2=q(q+5d),"#“%0,'(=4.ᦑ⌱+A.ூ./௃1⚪ὃ45
6ᦪᑡ
ᦪᑡḄ819Ḅ:ᙠὃ4<=Ḅ>?.

78.Cூ'᪆௃᪷EFᦪḄ᜻ᏔឋJFᦪᙠ00,2.•./஺V=op>0,᣸◀⌱⚗O,2+2ᦑ⌱+C.ூ./௃1⚪r⌕ὃ45FᦪḄ᜻ᏔឋḄᑨuJ᜻ᏔFᦪ\vḄabឋw_x᫏⚪.9.Bூ'᪆௃᪷E{|Fᦪ}
Q~ᡠᨵ.Ḅᙶ᪗ᯠQᓽP.ூR'௃sinx=cos2x,ᡠ[sinx=-lᡈsinx=/.xw[-»,2ᡠ[=,ᡈ=(ᡈ%=ᡈ%=Kᡠ[Fᦪ/'TxV=cos2xTxe[—2VḄ\]FᦪgTxV=sinxḄ\].Ḅᙶ᪗ḄTC3ᐔTC5TC-s=------1----1---1---=2"ᦑ⌱B.2266ூ./௃1⚪r⌕ὃ4FᦪḄ\]JQὃ4ᦪ<¡¢ᦪ<£Ḅ᪶¥¦§.10.Aூ'᪆௃11ᵫgV=J7>mE◀⌱⚗஺;_᜛=+7<°᣸◀⌱⚗GᵫFᦪ/GVᨵ²ᦪ|³.᣸◀⌱⚗/3,µ¶P·¸.ூR'௃ᵫ/3=+7>0,P᣸◀⌱⚗¹,ஹ»P᣸◀⌱⚗Gᵫ¥V=0Pᐔx=½¾=*ÀᓽFᦪ/tvVᨵ²ᦪஹ2MI=-e<0|³.P᣸◀⌱⚗6,ᦑ⌱A.ூ./௃

8~⚪®M¯8°±Ḅ⌱}ὃ²³ᦪḄ°±Qឋµ#¶.;᫏⚪.)¸⚪¹º»
ὃ¼½Ḅ¾⚪aᔣ#¿⚪¹ḄᱯgÁᔠឋÂÃஹὃ²IÄg¯#ÅÆ¡ÇÈÉ.{)¸⚪¹eʯa☢ᐭË#᪷̳ᦪḄÍஹEÍஹᓫÎឋஹ᜻ᏔឋஹᱯÑgeÒ10+,Ó-0\-+84Õ¨³ᦪ°±ḄÖᓄØÙ#ᑭᵨ᣸◀Ü#Ý¡ᔠ⚪ÞḄ⌱⚗᣸◀.11.Dூ᪆௃᪷Ìßᦪ#ᓽà᧕'âã.ூ௃z3_-z(l-Q11.Z-T+7-(l+z)(l-z)-2ᦑ⌱wD.ூgå௃~⚪ὃ²ßᦪḄᑣ#¶çẠ⚪.12.Dூ᪆௃V+Jé^_,ஹ=ly-2|+/Qx=5êᡂḄìíîÍ#ᓃÕ⊤ìíîÍᑁḄg2qg2-஻$_Ḅð᳛#ᯠóᔠ°ôx-2'âᡠ'ê.ூ௃é^_.ஹ•=|Ó-2|+/Q.\”3êᡂḄìíîÍ#᝞°▢úûᑖᡠ.ᵫ⚪ÞâgA,BḄᙶ᪗ᑖOP

9.12-(-1).•%=Ã=/%=Ä-=-3••kN1ᡈkW-39y+/I.——ḄÇÉY(-8,-3]U[l+8).tx-2ᦑ⌱D.ூ./௃y4-7'1⚪ḄᐵÌᨵ{|+Í᪷EᦪηᔠḄÐÑQ'Ò⚪ᓽÓÔÕ{.Ö×ØḄÙ᳛g»Í⌕ÛÜÝ~{Þx-2ØᡠÉᡂḄßàáâ.ὃ4ãᓄ>?wឋ·ᔠḄ>?w_8Ạ⚪.»ஹæç⚪+1⚪ᐳ4é⚪êé⚪5ᑖᐳ20ᑖ஺13.n[k7r+—,k6+7],keZ2ூ'᪆௃ᓄìFᦪḄ'᪆ᑭᵨïðFᦪḄ\]ឋñQ'ᓽP.ூR'௃Fᦪ/(jOnCOS:Xn/cOSZx+g,•••ᨬéÛᕜùT===û22ᦇ4+ýþ¥2%+2keZ,ᦇ+^ᦔ!k%+keZ,TTᡠᓫ⌴+],■+%],k0z.7Tᦑᫀᐔ<[k">,k7Z+7t],keZ.ூ"#௃%⚪'⌕ὃ*+,-.Ḅ0Ḅ1ᵨ345ᦪḄ789ឋ;<=>᫏⚪.14.5Vn+ூF᪆௃HPMfḄᕜMᨬOᓽQIPᵨI+IPEIᨬOTPUVᱥXYXḄᚖXᚖ[஺]ᓄQIPMI+IPQIᨬO,ᦪ`aᔠᓽQF.ூcF௃᝞7eVᱥXC/=8yḄᯖ"eClm"M(-4,3),VᱥXCr=sḄᯖ"e(0,2),YXuvy=-2.TpxYXḄᚖXᚖ[Q,ᑣᨵIPRHPQI

10\PM\+\PF\=\PM\+\PQ\>\MQ\=5,üWýüþ,P,Q7gᐳ_¨#ÿᡂᡠAPMFḄᕜᨬ5+7-42+3-22=5+717.ᦑᫀ5+V17.⚪ὃᱥḄᵨὃᦪᔠᦪ!"ᓄ$%&'()*᫏⚪.115.-4ூ.᪆௃ᐜᑖ᪆34ᦪ5Ḅ678ᯠ:᪷<=>ᭆ@*Ḅ8A@ᓽCD.E“ាH34ᦪ”Ḅᭆ᳛.ூK.௃LMN34ᦪOxe[O,2],678N2-0=2,oPQ[<2]5Ḅ678N2-R6=8,ᡠ“X஺ាH34ᦪ”Ḅᭆ᳛NP=I=.o4ᦑᫀ4ூUV௃⚪ὃ=>ᭆ@*Ḅ8A@W8X᧕..Z⚪Ḅᐵ\N]ᑨ_E`᪗bc5Ḅ678.16.[2,4|.ூ.᪆௃/e%g=-3/+6%i&DE⚔UkElmDE/஺g=-95ḄnopᔠqᦪlmᓽCD..ூK.௃

11/(x)=-3x2+6x=-3(x-1)2+3,⚔"(1,3)5ᦪḄ[-9,3],m32+6=-9=-1ᡈx=3.5ᦪf\x)=-3x2+6x78Ḅx=1,/প=3,ᡠb—aḄফ4].ᦑᫀ:[2,4].ூ"#௃%⚪ὃ*5ᦪὃ*ᦪ`aᔠ¢£<=¤Ạ⚪.¦ஹF⚪ᐳ70ᑖ஺F1ᑏ«ᦻ®¯ஹ°¯Tvᡈ±²³´஺17.(1)µF᪆(2)°¯µF᪆.ூF᪆௃(1)¶a=l¸Q5ᦪḄ¹ᦪ/'(%),ᑨ¼¹5ᦪḄᓫឋ½²/'(1)=¾1+1-1=0ᓽ¹5ᦪḄ¿";ফ¶a=()¸ᑖÁÂÃxḄÄ5ᦪ஻(x)=e'+cosx-x/nx-l,½²Ä5ᦪḄᨬ°¯/(x)

12(2)°¯¶a=0¸/(x)=x/nx,জÒOVxW1,ᑣex+cosx-1>O»xlnx<0ᡠ/(x)l,Ùh(x)=ex+cosx—xlnx—1,ᑣ(x)=e*—sinx—Inx—1,x)=஻'(x),ᑣÏ(x)=e*-—cosx,x>l,ᡠᡄ(x)>e—1—E>0,ÜÝÏ(x)ᙠ(1+8)lᓫ⌴ᡠw(x)>m(1)=e-5ml—1>0,ᓽm(x)=஻(x)X),஻(x)ᙠ(1+°°)lᓫ⌴ᡠ/z(x)>/z(l)=e+cvAvl-lX),ᓽxlnxᦑ(x)G_L☢BEE.

13(2)᝞#ᡠB,C
ᙶ᪗ᑣ4(1,0,0),8(1,2,0),H(0,2,()),-0,1,1),J=(1,-1,-1),L=(1M,N1),J=(0,1,-1).O☢AFBḄᔣP஻=(Fy,zJ,FA-n=0WZ]=0᳝=4ᑣ__n=4FB-n=0M+y—Z]=0[=஺'^%=1,n=(l,0,l),ᵫ(1)&a☢EEBḄᔣP〈=c=(0,1,1),n-m1_1:.cos-72x72~2ᵫ#&a'☢A—BF—Elm'☢ᡠn'☢A-M-EḄᜧ,lo.ூq௃s⚪ὃuvw☢ᚖḄᑨz☢☢ᚖ{w☢ᚖḄឋ}~ᵨ
ᔣ'☢Ḅᜧ,᫏⚪.19.(1)12-3103;(2)12᪆(3)12᪆.ூ᪆௃3?Y2(1)ᦪ)=¥\/஻x(xுl)Ḅᦪᵫl3ᔴḄ▭ᡂs.(2)ᡠ⌕12¡ᓄl1221nx—x+3<0,᪀⌼ᦪ/?(x)=21nx—x+J,ᑭᵨᦪ1/z(x)<0,ᵫ1ᡂ.஺1஺1\1(01\(3)ᑭᵨফḄ!§ᑨ¨O=="-Nᓲ7>-ln,ᵫ!ᔠ¬ᦪ®15>lnll.604/1-1412஻-12/1+1y2\2n-\Jூ
௃3?r2(1)±ly=^^lnx,(x>l)X—1

14._32x64%lnxᡠn'´Nµ¶x=3y|=12-31n3J=3(2)⌕1¸<16,XX2-111º◤121nx<'--=ᓽ121nx-x+—v0,XXXO஻(x)=21nx-x+L½¾)=N¿1_<0ᡠnᝢxÁᙠÃ1,ÄÁ¸ᓫÆ⌴È,ᡠn஻(x)ீ஻প=0ᡠnË<16,ᓽÌ<16X2n_1(2஻+12"-1]Ã3Á±ll4஻2-1—42஻-12n+lJÍᵫÃ2Áax>lx-->2

15xx2஻+12n—l…f2n+lᡠn----->21n-----2n-\2Ð+112஻—1ᡠn%>|ln2஻+1]2஻-1JᡠnSeo>gÃln3+ln|+-+lnj^Á=glnl21=lnllூq௃s,⚪Õ⌕ὃuᦪḄÖ®ὃuᑭᵨᦪ12ὃu×Ø12ᦪᑡÚ⚪.20.᪆ூ᪆௃Û⌱Ýজ!ᔠß$Ḅ☢àá^4S=4x^-bcsinA=b2+c2-a2,ᓄâᑮsinA="Nᓝ'ஹ=cosA,ᑣ22hctanA=l,Í0°

16Í+4=஻+/22Z?c,Z?c<44-2\/2>íî஺=c=j4+2>/5ïᡂS=—fccsinA<—x(4+2\/2)x-42+1,ᦑAABCḄ☢àḄᨬᜧla+1h=c="+2&.Û⌱Ýঝa=b=2,!ᔠß$Ḅ☢àá,^4S=4x-hcsinA=h2+c2-a2,ᓄâᑮsinA==cosA,22bcᑣtanA=l,Í0°

17ᡠCr஺2ḄsU᩽ᙶ᪗A0v,+V,312,z+B.ᡠSMBC=^\OA\-\OB\sinZAOB=6.ᦑA4O8Ḅ☢|G.ூUV௃⚪ὃ}~ᦪ&&Ḅ"ᓄᙶ᪗&᩽ᙶ᪗Ḅ"ᓄᑭᵨ᩽ᙶ᪗D☢|()*᫏⚪.22.(1)2(2).᪆ூ.᪆௃(1)f+2V+3z2ᓄ(V+z2)+2(y2+z2),ᑭᵨᓽCDEᨬ4,CEḄ(2)᪷<ᱏ+/2221aq^2(a2+h2)>(a+bf,EV+4y?+gz?N^(x+2y)2,ᑭᵨD7EᨬCE”?Ḅ.ூK.௃.^(1)ᵫ⚪CX,y,Z£R,z(x+2y)=mx2+2y2+3z2=(x24-z2)+2(y2+z2)>2xz+4yz=2m=4,••ITl=2(2)Va2+/?2>2|afe|,:.2(a2+Z?2)N(a+஻Ax2+4^2+^z2>^(x+2y)2+^z2>1-2|(x+2>')z|>l,|m|>1,ᓽmW—1ᡈmN/.ூUV௃⚪ὃḄᵨᑭᵨr'Dᨬὃᓄ].