河北省丰宁县2022-2023学年数学九年级第一学期期末调研试题含解析

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2022-2023
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17/⚪dlᦪஹlᦪXêëஹᐗäåäåìᔠ⚪í&dîY⚪¾⌕ὃ@A#ḄYஹlᦪḄ7¥ஹlᦪ᪆`Ḅb§lᦪXᐗäåḄᐵï/⚪ᐵᙠD*জÉḄᕜÒᨬµ¦⚪Hᓄd}Sñᨬµ¦⚪ᑭᵨYḄឋ⚪4ঝÉlᦪXlᦪḄZ=©ᦪ¦⚪HᓄdᐗäåÂᦪ᪷Ḅ©ᦪ¦⚪.21ஹ2ூ᪆௃+ÏᑭᵨòᢣᦪôḄឋ§ᱯõḄlᦪ]ö]Ḅឋᑖᓄ¿P'pᫀ.ூ)௃*ø`=-1+2-ḕ+6+1=2ூ=>௃c⚪¾⌕ὃ@AÂᦪx:;ᓄ¿ᔜᦪ⚪ᐵ.22ஹy=—X2+4X+2.ூᑖ᪆௃᪷=3Ḅᙶ᪗%b'ÙḄ]ᑏ'lᦪḄ᪆`üb'=AḄᙶ᪗ᨬJᑭᵨ=AஹB}=Ḅᙶ᪗bQᱥSḄ᪆`.ூ)௃(1)\,+Sy=-4"ÙØ=3(3,9),#.9=-4X3+"P*m=L.,.+SḄ᪆`dy=-4x+l.:A(5,n)ᙠ+Sy=-4x+lW஻=-4X5+1=1,.,.=A(5,1),É=A(5,1)ஹB(3,9)Êᐭy=-*2+ᡭ+

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18=4-[c=6.•.tᱥhḄ᪆0-+᪗+2.ூ23௃4⚪ὃ9ᑭᵨ<ᦪ=(\dᦪḄ᪆<ᦪ⚪Ḅᐵ?.23ஹ(1)y=-M(4,2)M(2)xV4ᡈ0VxV4M(3)P(2&')ᡈP(2,4).x71kூᑖ᪆௃(1)A(a,-2)ᐭy=-x,A(-4,-2),A(42)ᐭy=-,¡dᦪḄ⊤£02xQc᪷2B2Aᐵ%¤2¥¦ᓽᑮBḄᙶ᪗Mx(2)§¨dᦪK©ᵫ«2ᙶ᪗ᓽ=MQ111R(3)lP(m,ᑣC(m,—m),᪷APOCḄ☢03,cmx|—m-⁐|=3,=mḄᓽm222mᑮ2PḄᙶ᪗.ூ௃(1)A(a,-2)ᐭy=Mxa=-4,/.A(-4,2),A(-4,-2)ᐭy=",k=8,xQ...¡dᦪḄ⊤£0y=2,x•:2B2Aᐵ%¤2¥¦AB(4,2).Qᦑᫀ0-y=—;(4,2)Mx1k(2)7x.—V0Ḅ¯xV4ᡈ0VxV4M2xo1(3)lP(m,—),ᑣC(m,—m),m211Q±⚪G7mH7m.—1=3,22mm=2j7ᡈm=2,(²³´µ)..P(2&,)ᡈ(2,4).7ூ23௃

19⚪ὃ9¡dᦪc\dᦪḄ«2¶⚪⚪ᐵ?ᙠ%¡dᦪc\dᦪḄK©Ḅ«2ᙶ᪗¸¹dᦪḄ᪆.24ஹ(1)5cm(1)ᨬᜧ800cmIூᑖ᪆௃(1)l»ᣵḄ½,Ḅ:0xcm,ᑣAB=(40-lx)cm,᪷¾¿ḄÀ☢0484cm௃ᑡᓽM(1)l»ᣵḄ½,Ḅ:0xcm,¾¿ḄÁ☢0ycmlÁ☢=4,☢Mᑣy=-8x4160x,Â=ᨬ.ூ௃(1)l»ᣵḄ½,Ḅ:0xcm,ᑣ(40-lx)1=900,ᓽ40-lx=±30,xi=35(Ãᔠ⚪G´µ)xi=5#-»ᣵḄ½,:05c,஻M(1)l»ᣵḄ½,Ḅ:0xc,஻¾¿ḄÁ☢0ycmlᑣyxḄdᦪᐵ<0y=4(40-lx)x,ᓽy=-8x'+160x,j=-8(x-10)i+800,-8<0,.••yᨵᨬᜧ.•.yx=10|yᨬᜧ=800#-ᢚᡂḄƾ¿ḄÁ☢ᨵᨬᜧÇᨬᜧ800c,M.ூ23௃4⚪ὃ9cᐗ(\ḄÈᵨ(\dᦪḄᨬ¶⚪᪷ÉÊK,ᳮ᝞ÊËÌcᐗ(\dᦪᐵ<⚪Ḅᐵ?MÍν,☢=:x:,☢=ஹÏMᳮƾ¿ḄÀ☢Ð,M⚪|ÈÑÒG᝞ÊᑭᵨÂ=dᦪḄᨬᜧ.25ஹ(1)ÓÍB᪆M(2)CDf-l.ூᑖ᪆௃(1)᪷⚪GᐜᵫBC=BA=NACB=NCAB,᪷"+,ᑁ+=NABC=90°,ᓽYÖM(2)᪷⚪Gᐜ=×ØOD,᪷ÙÚᳮᓽ=OC,ÛwCD.ூ௃-(1)ÓÍ-•.•BC=B4,NC4B=45஺ZACB=ZCAB=45°,

20ZABC=180°-45°-45°=90°,ᓽAB_L3C,Ý8C஺஺Ḅᑗh.(2)ᵫ(1)ßZABC=9Q°,Q4?஺஺ḄgØ:.OD=OB=-AB^\,BC=2,2.-.OC=V22+12=>/5:.CD=OC-OD=45-l.ூ23௃4⚪ὃ9ᙊḄᑗhḄᑨῪ"+,ḄឋäåæÙÚᳮᑗhḄᑨçÛèéᳮêëì¶⚪Ḅᐵ?.AB26ஹ(1)B᪆M(2)஺OGᚖgᳮᵫB᪆M(3)y——=1|îOG0Ὺg+"+,ᳮᵫB᪆.ACூᑖ᪆௃(1)ᵫ¡hïßᡃñ◤⌕ÓÍᵫ+¥ÈᓽÓM(2)ᵫó,Ḅᑨᳮßô:,AFEG0ó,᪷ó,Ḅឋäæõ"+,ḄᑨᑮAAFOsaCGO,öwÃ÷ᑮYÖM(3)ᐜᑨø஺=OG,ᑭᵨi+Ḅù+ᑨøNAOF'=Na)G,NA4O=NC,A4O&CDG,ᓽYÖ.ூ௃(1)ÓÍ-ᙠA4OCAEGCúVZADC=ZEGC,NC=NC,.AADC^/\EGC..EGCG*'AD-CD"(2)-FOOGᚖg.ᳮᵫ᝞U-ᙠô:,4FEGú■:ZFAG=ZAFE=ZAGE=90°,ô:,4FEG0ó,..AF=EG...EGCG•⁰cw‘•._CG#AD-CD'ý•.•A5C0g+"+,ADA.BC,

21ZFAD=ZC=90°-ZDAC,:•AFDsACGD..NADF=NCDG.,:ZCDG+ZADG=90°,:.NAD+NADG=90஺.ᓽ/ᡝDG=900..FD.1_DG.AR(3)
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