广东省东莞市某学校2022-2023学年数学九上期末经典试题含解析

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2022-2023
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14
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MN=3,8M(x,----),x!]x=2+3=5ᡈx=2-3=-1QQx=5---=---x5QX=-1---=1,X8AM(5,-)ᡈ(-1,8).OQᦑ/ᫀ=(1)y=-(2)M(5,-)ᡈ(-1,8).x5ூ௃⚪ὃ^+ᦪ+ᦪḄH⚪⚪Ḅᐵ2ᵨk-lᦪms^+ᦪḄ᪆r,ᑭᵨᦪᔠḄ⊤!Ḅ☢p/⚪Ḅᐵ2.21-(1)xi=2,X2=5(2)x=.þ
(3)x=-L5ᡈx=23ூᑖ᪆௃(1)ᵨrᑖmsd(2)ᵨqrmsd(3)ᵨD)s.ூ௃:(1)x2-7x+ll=l.(x-2)(x-5)=1,x-2=lᡈx-5=Lxi=2,X2=5.(2)=(-4)2-4X3X(-1)=28,

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s&Ḅ¬d(2)᪷oµ¶-ᳮsAḄᙶ᪗ᯠ°ᑭᵨk-lᦪmsRA5Ḅ᪆r¸N^+ᦪḄ᪆rὶºsMḄᙶ᪗ᯠ°᪷o!☢pqrᓽ
sA80MḄ☢p.ூ௃(1)♦.•R/UVNNḄ¼ᙶ᪗=1,39..y=—xl=—,429.N(1,-),2•.•Nᙠ^+ᦪy=(x>0)ḄX9A*=lx-=272(2)•••AᙠR,

16••A(/n,—/n)4VOA=10,ஹ3m2+(—஻2)2=1()2,!"m=8,4).A(8,1),VOA=OB=10,:B(10,0),%&ABḄ!᪆)*y=ax+b98m+n=6fzn=-3•./,!"10m+n=0஻=30%&ABḄ!᪆)*y=-3x+30,y=-3x+30x=1x=9!27"ᡈ4y=1J=27஺=3IX).M(9,3),:..BOMḄ☢7=—x10x3=2.2ூ9:௃<⚪ὃ?@ABCDᦪF1GDᦪḄH9I1GDᦪJKL9Ḅᙶ᪗ᱯPIQRSᦪTUABCDᦪḄ!᪆)V1GDᦪḄ!᪆)IU"Aஹ"9Ḅᙶ᪗X!⚪ḄᐵZ.24ஹ[1\y=--x+8][2\^x=10_ᐗaIᨬᜧᨴeᑭ*7_ᐗ2ூᑖ᪆௃[1\᪷iDᦪJKIᑭᵨQRSᦪTU!k"][2\᪷i“mᑭn=ᓫpᑭnx├rs-mtu”ᑡxDᦪ!᪆)IᵫzGDᦪḄឋ|k"ᨬ}.ூ~!௃[1\=1«+1\,9[6,5\ஹ[8,4\ᐭI"'6k+b=5'8+஻=4'[!"2,[b=8

17:.y-x+8]2(2)᪷i⚪"z=(x-4)y-11=(x-4)(-—x+8)-1121,=--x2+lOx-432=--(x-10)I+7,2.•.^x=10_ᐗaIᨬᜧᨴeᑭ*7_ᐗ.ூ9:௃<⚪⌕ὃ?zGDᦪḄᵨIQRSᦪTUDᦪ!᪆)zGDᦪḄJKVឋ|X!⚪ḄᐵZ.x225ஹ---]x=2aI)=—.x+13ூ!᪆௃ᐜᑁḄᑖ)ᑖIᢥ᯿ᑖ)Ḅ◀TTᑣI◀T¡ᓄ*£T¤¥¦§.ᨬ¨ᙠ-1ª«¬1®¯ᑖ)ᑖ°V◀)±*1ḄᦪᐭU}.x(x+l)X~|x(x-l)x2(x-1)2Xூ~!௃!.)=----i---------L----------------------------------------5----------------2-=--------------------------------i--------i—=----------ூµ!௃!.(X+1)(-1)J(X-1)(X+1)(X-1)x(x-l)x+1.XTTSxS3Ḅ᦮ᦪᨵ11,1,1,2,3,^x=-lᡈX=1aIᑖ)Ḅᑖ°*1,^X=1aI◀)*1,...xḄ}aI±kx=Tᡈx=lᡈx=l.22±ºx=2,»a)=——=-.2+1326ஹ(1)y=-10x+500](2)^├rp¼R*38ᐗaI½ᦻᐹÀᜩḄ├rᑭnᨬᜧIᨬᜧᑭn*1ᐗூᑖ᪆௃(1)᪷iÂ▭├rsÄÅ250-10(x-25),ᓄÆᓽk](2)ᑭᵨzGDᦪḄឋ|⚪¬È├rsÀÉᦻᐹᑭnḄÊËᩩÉIkU"Íᫀ.ூ~!௃!(1)y=250-10(%-25)=-10x+500ÀᜩḄ├rsy(É)F├rp¼x(ᐗ/É)ÐÑḄDᦪᐵS)*y=-10x+500](2)├rᑭn*ÒᐗIᵫ⚪"w=(x-20)(-10%+500)

18=-10x2+700A--10000=—10(x—35>+2250-10^+500>103818V-10<0,½ᱥRḄ]¾¿=Rx=35½ᱥRCᔣÁᙠ]¾¿ḄÂÃÄÅxḄÆᜧÈÉÊ...x=38"Ëᨬᜧ¬=1./├ÎÏÐ-=38ᐗÑᦻᐹÔᜩḄ├ÎᑭÖᨬᜧᨬᜧᑭÖ=1ᐗ.ூ௃⚪×⌕ὃÙᐗ¥N+ᦪḄ&ᵨÚÛᑡr⚪Ḅᐵ2.