2022年天津市滨海新区中考二模 化学 试题（学生版+解析版）

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2623.¾¿ÀÁᙢᜐÄ¿¤¾¿lÅÆ-ᜩᯠḄÅÆÈÉ஺(1)“ᩖÎlϤ᱄”⊱◖Ó“¹ÏÔᜩÕ”ᙠ³Ö×ØÙᩖÎlÏḄÚJÛᡂÜ×ØÝÞ〉àᙠáᙢâãäḄ“¿lÏ”஺জ“ᩖÎlÏ”åæçèçèéêᜧëì⃩îïaḄঝ“¿lÏ”åæẬẬ-ñò◤Ḅ(⌱“óô”ᡈ“ô”)ᐗï஺(2)◀÷ᓄøaᩖù஺]Þ◀÷NaClaæᨵ_ôḄMgCLஹCaCbNa2sO4ᩖ⌱ᵨNa2cChஹ⏚ஹBa(0H)2$%&ᑺᢥ)*Ḅ,-./᝞1ᡠ3Ḅ45஺f89.)»I<=mI4?11:BᐭDEBFᵨGHIJ45KLMᩖḄNaCl|'(ᓟ*JQঝ+'ᐭ〉.NaCtG)---------------DQ--------------UVWᑡY⚪Lজ45I\Bᐭ&ᑺA◀_Ḅᩖ`஺ঝ45II\BᐭḄ&ᑺB`஺ঞQঝ\MᨵḄ▢deᨵ(fᦪh)%஺ট45HI\jkḄ\lmḄᓄopq஺ூVᫀ௃(1)জ.vwঝ.xE(2)জ.yᓄ╅ஹ{⏚|ঝ.}⏚|ঞ.3NaOH+HCl=NaCl+HO2ூ᪆௃ூY1௃ᜧ⃩ᒹஹvwஹᾦஹkஹ஺9ᜧ⃩\Ḅvw஺◤ḄEᐗᒹஹ}ஹஹஹ┛ஹ¢ஹ£ஹ{ஹ|ஹyஹ╅஺Ậ`◤ḄxEᐗ஺ூY2௃45I\Bᐭ&ᑺA`ᓄ¥ᓄ¥¦yᓄ╅lmkᡂᓄ╅89yᓄ¥¨ᓄ©ª¦{⏚|lmkᡂ{⏚¥89ᓄ|஺ᡠ«45I\Bᐭ&ᑺA◀_Ḅᩖ`yᓄ╅ஹ{⏚|஺45U\BᐭḄ&ᑺB`}⏚|}⏚|¦yᓄ┛lmkᡂ}⏚┛89yᓄ|¨}⏚|¦45I\kᡂḄyᓄ¥lmkᡂ}⏚¥89yᓄ|¨}⏚|¦45I\ᒕWḄᓄ¥lmkᡂ}⏚¥89ᓄ|஺◀_Ḅᩖ`yᓄ┛ஹ45I\kᡂḄyᓄ®ஹ45I\ᒕWḄᓄ¥஺ᓽ45nᑮḄ89`}⏚┛}⏚©ªLQঝ`ᒕWḄ}⏚|ஹ45IஹIIkᡂḄᓄ|ஹᜧEḄyᓄ|஺

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28CaCO+2HC1=CaCl+H0+CO2T32210044x0.88g100xØ=dÚËx=2gீ4.9g,ᑣ⁐·a\Þᨵᐸßᱥᵫ⚪ºáᓄ|º«¦{⏚╅lmkᡂᓄ╅89ᡠ«·a\Mᨵᓄ╅ḄEÀ4.9g-2g=2.9g,·᪵¹\)*Mᨵᓄ|{⏚╅Ôkᡂ2.9gᓄ╅89ᡠ◤Ḅᓄ|EÀ{⏚╅EÀz,MgSO+2NaOH=MgåOHæ,J+Na2so,ফ48Q12080583rᜧì=⊈Ë…gyZ2.9gz=4g,ᵫñºá·᪵¹\)*Mᨵ}⏚┛ஹᓄ|{⏚╅EòÀ2g+6g+4g=12g,ᑣ·᪵¹\)*Èᨵ{⏚£஺ôñᡠõ·᪵¹\)*ᨵ}⏚┛ஹᓄ|ஹ{⏚╅)*Èᨵ{⏚Éஹ{⏚£BËᑮ·aÀᓄ╅}⏚┛öᓄ|{⏚╅ាøùᐰlmkᡂᓄ╅89{⏚|⁐À{⏚|Bᐭyᓄ⚞yᓄ¥¦{⏚|lmËᑮ⁐·cÀ{⏚¥89¨ூY1௃ᵫñºáÅbÀµᓄ}ᓄqÀCO?¨ூY2௃ᵫñºá⁐·aḄᡂᑖ`ᓄ|ᓄ╅ᓄqÀNaOHஹMgåOHæ¨2ூY3௃ᵫñºá·᪵¹\)*Èᨵ{⏚É{⏚£¨ூY4௃ᵫñºáyᓄ¥¦lmkᡂḄ{⏚|lmkᡂ{⏚ý89yᓄ|þlmᓄopqÀLNaSO+BaCl=2NaCl+BaSOJ஺2424ஹÿ⚪ᜧ⚪ᐳ2⚪ᐳ10ᑖ25.⊈G0H12N2O⁚Ḅ⌕ᱥ஺"#ᑖ$⊈%&ᜮᾯ⏨*+,-.஺□ᐝஹ2ஹᨽ4567ᐸᑖ$஺9:ᡂ<ᑡ>஺1⊈?@ᨵCᦪEFᐗ஺2⊈ᑖH?IஹJKHḄLᦪMNᑏᨬQM஺3⊈?SᐗTUᐗḄVMNᑏᨬQM஺

29(4)88g⊈?SᐗVNg«ூYᫀ௃(1)4(2)5\6(3)7\4(4)14ூ]᪆௃ூᑖ᪆௃⚪_`ᨵᐵᓄcdḄefᑖHVஹKHLᦪMஹᐗVM`ᐗVgeᐵ>஺ூhi1j]௃⊈(CIOH,N0)?@ᨵIஹJஹSஹUkFᐗᦑC\4m22ூhi2j]௃⊈ᑖH?IஹJKHḄLᦪMN10:12=5:6,ᦑC\5:6mூhi3j]௃⊈?SᐗTUᐗḄVMN(14x2):(16x1)=28:16=7:4,ᦑC\7:4mூhi4j]௃⊈(CIOHN0)ḄefᑖHVN(12X10)+(1X12)+04X2)+(16X1)=176I222888g⊈?SᐗḄVN88gxnxl00%=14g,ᦑC\14஺176ூop௃q⍝ᱥVsᓄcd?ᐗVᑣᐗV=ᱥVxᐗVᑖᦪ஺26.ᡃwᓄcxyz{|}~yᑴNᑴ~ᩲ஺ᙠ▭ḄI⏚?&ᨵVḄᓄ஺ᨵ᪵N᪵?I⏚ḄVᑖᦪ᪵12g,ᐭ80g¢?£ᐸ:ᐰ¥]¦§ᐭ¨©⏚43.4g,ា«:ᐰ¬®#ᐰ¯⍎±ᑮᓄḄ³⛳T¥µ131g஺9>\(1)ᡂ¶UᓄIḄV஺(2)᪵?I⏚ḄVᑖᦪ(>·¸¹ºᑮ0.1%)஺(3)¬»ᡠ±¥µ?¥ḄVᑖᦪ஺ூYᫀ௃3)᪷¿VÀឤ¬ÃᱥḄÄVT¬»ᱥḄÄVeg஺ᑣCO2ḄV:12g+80g+43.4g-131g=4.4gY\ᡂ¶UᓄIḄVN4.4g஺(2)Æ᪵?I⏚ḄVNx,ᡂᓄVNy

30Na2cO3+2HC1=2NaCl+CO2T+HO210611744xy4.4g106_x117_y444.4g444.4g]±x=10.6g,y=11.7gKᔠᱥ?I⏚ḄVᑖᦪ\2ÈxlOO%=88.3%12gY\᪵?I⏚ḄVᑖᦪN88.3%஺(3)ᡠ±¥µ?ᓄV\11.7g+12g-10.6g=13.1g13la¬»ᡠ±¥µ?¥Vᑖᦪ\Éxl()()%=10%131gY\¬»ᡠ±¥µᙠ¥VᑖᦪN10%஺ூ]᪆௃ூhi1j]௃ÊYᫀmூhi2j]௃ÊYᫀmூhi3j]௃ÊYᫀ஺

31