2022年四川省遂宁市中考数学真题（解析版）

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14ὃ«¬ᜓὃ¯ᧇὃ«⚪±²³´µ᪵¶ஹ·⍝¹¶ஹºᵫI¶ஹᓫ»¶⚗(½q▲⌱1⚗)ᑴÂ᝞Ĩ³Å(ÆᑖÇÈÉÊ5).ËÌ᪷,ÅÍÎÏḄÇÈ(ÄᑡV⚪(1)ᙠÑ8¢wÍᐳ¢wÒÓÔÕ᪥ᐳᨵ2000ÒÓÖ³᰿ص᪵¶ḄÓᨵq#(2)⊡ᐰᩩܨ³Å#(3)Ý·⍝¹¶Þ/ஹµ᪵¶Þ8ஹºᵫI¶ÞCஹᓫ»¶Þ஺᪥áJÑ"⚗Í5â⚗ᩭäåsæËᵨç᪛éÅᡈᑡ⊤Ḅ£=5ᑮ⚗Íាᨵ⚗ºᵫI¶CḄᭆ᳛.ூᫀ௃(1)100,800(2)⊡ᐰᩩܨ³Åð(᪆(3)᪛éÅð(᪆ᑮ⚗Íាᨵ⚗ºᵫI¶CḄᭆ᳛gூ(᪆௃ூᑖ᪆௃(1)ᐜᑭᵨµ᪵¶Ḅqᦪ◀3ᐸᡠ7Ḅ÷ᑖø2L¢wḄEqᦪ#ùᑭᵨ2000ú3µ᪵¶ḄqᦪᡠᓰḄ÷ᑖøᓽ2=(#(2)ᑖü=5ᓫ»¶ḄqᦪºᵫI¶Ḅqᦪᓽ2=(#(3)᪷,⚪^ç5᪛éÅ2LJ⚗ÍýOâ⚗ḄᡠᨵþᙳḄᐳᨵ12ᑮ⚗ាᨵ⚗ᵫCḄᨵ6.᪷ᭆ᳛"#$ᓽ&'.ூ)*1+'௃'-./Ḅ01ᦪ40+40%=100192000x40%=800A9ᦑ>ᫀ-100,800ூ)*2+'௃'-ᓫBḄ1ᦪ100x10%=101C15⚓ᐳ27⚓

15ὃFGHᜓὃJᧇὃFH⚪MNᵫḄ1ᦪ100-40-20-10=301,⊡ᐰᩩTU#V᝞X-'-᪷⚪YZ[᪛]V᝞X:
_`⚗abc⚗deḄᡠᨵghᙳḄᐳᨵ12ᑮ⚗ាᨵ⚗ᵫ஺Ḅᨵ6.••ᑮ⚗ាᨵ⚗ᵫCḄᭆ᳛==<.122ூmn௃o⚪p⌕ὃ/rᡧTU#VtᩩTU#Vᵨ᪵ow#0xᑭᵨ᪛]Vtᑡ⊤|&ᭆ᳛}~⚪Y~_U#Vb'⚪Ḅᐵ.21.ᙠ☢ᙶ᪗᝞mḄᙶ᪗ᙶ᪗ᦪᑣm“m᝞(-1/)(2022,—2022)“m”.(1)&¡¢£=¤^¦Ḅ“m”9X(2)§¨ᱥ¢y=ax2-7x+c(aஹc¯ᦪ)¦ᨵ°±ᨵ“m”²஺>1´&cḄbµ·.ூ>ᫀ௃প.=/¦Ḅ“m”(3,-3),(-3,3)x(2)0

16ὃFGHᜓὃJᧇὃFH⚪MNூᑖ᪆௃1¼¡¢½=¤^¦Ḅ“m”¾¿,¿À᪀ÂÃÄ&'ᓽ9X
2¨ᱥ¢y=ax2-7x+c
aஹcOPᦪR¦ᨵ°±ᨵ“m”Å[ÃÄÆ2-7Ç+஺=—x
awOᨵ°±ᨵ'A=36—4ac=0,ÈÉ.ூ)*1+'௃¼¡¢£=/¦Ḅ“m”¾Ê-gÀX-9ᑣᨵ஻z=—'È஻?=±3,m...½=ͦḄ“m”¾3,-3,
-3,3.ூ)*2+'௃¨ᱥ¢y=ax2-lx+c¦ᨵ°±ᨵ“m”•••ÃÄ-7x+c=X,H0ᨵ°±ᨵ'ᓽaf-6x+c=0A=36-4ac=0,ac=9,,9a=:•c';a>\,0

17ὃFGHᜓὃJᧇὃFH⚪MNூ>ᫀ௃ᛞ⚔ᑮᙢ☢Ḅæç£þù47ôூ'᪆௃ூᑖ᪆௃ÿEF
/GhᑣE//J.NG,3BPL/GᑣBFHPOVW,60=5x,ᑣZP=12x,᪷ᓽ.ூ௃᝞E
/GH,ᑣE//LNG,81ZGP,ᑣBFHP!":•FB=HPFH=BP.ᵫi=5:12,8P=5x,ᑣ4P=12x,ᵫBP2+AP2=AB2%&5x2+
12x2=,%x=2ᡈx=-2&()*ABP=FH=\O,AP=24,EF=a,BF=b,EFᙠRt^BEF,tanAEBF=—,BFᓽtan63.4°=ga2,-ija=2bজh*EHEF+FHEF+BPᙠRt^EAH,tanNEAH=----=---------=---------AHAP+PHAP+BFᓽtan50.2°=/3al.20ঝ24+bᵫজঝ%a=47,6=23.5.12ᛞ⚔ᑮᙢ☢Ḅ9:E;!47<.ூ=௃>⚪ὃABḄC▭EᵨGHᳮ⚪JKLMNOPQ⚪ḄᐵS.23.TOUVWᦪ,="-1&஺![ᦪ*\x]
4\^_`Wᦪ!=£
8ஹxCd8Ḅeᙶ᪗!-2.h18⚓ᐳ27⚓

18ὃklmᜓὃoᧇUὃkm⚪qL&1*sUVWᦪḄ᪆uvᙠ,wsxḄy2&2*sCḄᙶ᪗v᪷yᑏs}M

19ὃklmᜓὃoᧇUὃkm⚪qLᙶ᪗ᓽ²³sḄ☢.ூ´µ1௃2Ḅeᙶ᪗!-2ᙠ^_`Wᦪ¶=9Ḅy¢,.,.8Ḅᙶ᪗!(-2,-3),1B(-2,-3)ᙠUVWᦪg=ax-lḄy¢,;.-3=ax(-2)-1,%a=\,••UVWᦪḄ᪆u!xl,*/y=x-\,Ax=Oy=-\x=l,y=01••y(0,-1),(1,0),y=x-l2,6•.•UVWᦪ!=᝖-1![ᦪ)\^_`Wᦪ£=U
8ஹCd8Ḅeᙶ᪗!-2,x•CḄᙶ᪗!(3,2),ᵫy%}ᑘ

20ὃklmᜓὃoᧇUὃkm⚪qLூ´µ3௃228(-2,-3)\஺ᐵᡂ,,஺(2,3),஺]
ZCE,ªx=2¦ᐭy=x-l%1,(3-1)X(2-1)(3-1)X(3-2)+=222ᓽZC£)Ḅ☢Q2.ூ=௃>⚪ὃA^_`Wᦪ\UVWᦪḄ
µ⚪1>⚪ḄᐵSQÂH⚪JᑭᵨᦪÄᔠḄÆÇ1.24.᝞OOQNBCḄ᜜Ìᙊ஺ᙠ8c¢NA4cḄÐᑖÑ
஺Ò]BD,CD,஺BCḄÐÓÑ\4cḄÑ©
P.(1)Õ2POQOOḄᑗÑ(2)Õ2AABDS^DCP1(3)48=6,ZC=8,஺ᑮ“஺ḄØÙ.ூ1ᫀ௃(1)᪆(2)᪆(3)஺ᑮḄØÙ!U2ூ᪆௃ூᑖ᪆௃(1)ÒÌO஺ÕÂO»BC,ᑣ0DFDP,ᓽ%Õ(2)ᵫBC஻DP,/ACB=NADB,56NP=N4DB,᪷48OC!ᙊᑁÌÛNZ)CP+NNCQ=180°,56`4BD=NDCP,ᓽÕÂ46Z)s/DCP1(3)஺OELND£,ᵫZBDSADCP,᪷©áḄឋã%CP,ÕÂᔊåæ%ᙠRtVOEZ),ᑭᵨêëìᳮᓽ.ூ´µ1௃ÕÂ2ÒÌ஺£),h21⚓ᐳ27⚓

21ὃklmᜓὃoᧇUὃkm⚪qL•.7஺ÐᑖN8ZC,BAD=ADAC,BD=DC.ÛíBC!îï஺!8c,ðBC.';BC//DP,OD1DP.Ûñ஺஺!òî.•.POQOOḄᑗÑூ´µ2௃ÕÂ28C஻QP,ZACB=ZP.•••Z.ACB=NADB,ZP=ZADB.•••ABDC!ᙊᑁÌ,•••AABD+ZACD=\^°.a,:NDCP+4cz=180°,NABD=NDCP,ïAABDs2CP.ூ´µ3௃஺OEX஺E,!î•ZBAC=90°.VAB=6,AC=8,BC=>]AB2+AC2=10•a•;BD=DC,BD2+DC2=2BD2=BC2>•BD=DC=542■ᵫ&2b/yiBDsADCP,.ABBD••—,DCCPh22⚓ᐳ27⚓

22ὃklmᜓὃoᧇUὃkm⚪qLiBDDC5025Cr-----------=—=—,AB632549NP=/C+CP=8+—=.33ÛZ.ADB=NACB=NP,NBAD=NDAP,ABADSADAP,.AB_AD"7D~^4P'AD2=ABAP=98,•••AD=772.OEVAD,6...஺ᑮḄØÙ!ô.2ூ=௃>⚪ὃABᑗÑḄឋã\ᑨìᙊᑁÌö⊡©áḄឋã\ᑨìêëìᳮMN£¢OPQ⚪ḄᐵS.25.᝞ᙠÐ☢ᙶ᪗ø,ùᱥÑû=/+ý+஺\x]
4ஹ8d\y]
C,ᐸ,4Ḅᙶ᪗!(TO),CḄᙶ᪗!(0,-3).h23⚓ᐳ27⚓

23ὃklmᜓὃoᧇUὃkm⚪qL(1)ùᱥÑḄ᪆u(2)᝞1,EOAABCc4BFḄef"!¢ḄUÿ
஺ᙶ᪗(0,-2),஺'ᕜḄᨬ(3)᝞2,NC8Ḅ!
M#$ᱥḄ!
M,Nᙳᙠ(!)▲ᑁ
BஹN,-.4/Ḅ12
34ᑮx7Ḅ89:ANMN☢<2d,>ANMN?ῪABCD
NḄᙶ᪗.ூGᫀ௃(1)y=x2-2x-3(2)஺KLᕜḄᨬᔊ(3)NḄᙶ᪗(g,Oᡈ(1+ᦈ,—2+JUᡈ(6+W,3+X)ூY᪆௃ூᑖ᪆௃(1).\ᑭᵨ_`aᦪcYᓽe(2)f஺τ஺ᐵ-.Ḅhi
4஺ᐵ-.8cḄhi
k\஺lஹDfஹDD,ᵫhiḄឋpeq>AஹEஹFஹ஺2ᙠ1!.D
AOEEḄᕜᨬ}2
ᨬ஺Ḅt
uvwABOC?Ὺ.BABC
uᵫxy`ᳮYᓽe(3)k\⊤|}S“=2d,ev4W஻6N,u}.8cḄY᪆y=x-3,.ḄY᪆y=x+l,eMḄᙶ᪗(4,5),fNḄᙶ᪗(t,/-3),Mx7Ḅ/,Ny7Ḅx7-P,./-Qᑣ4=5&
AN=*++(—3)2
MN=y/(t-4)2+(t-8)2᪷?ῪABCḄឋp
ᑖজ4W=4ND
ঝ4A/=MND
ঞAN=MNj,ᑖᓽe.ூ1Y௃(24⚓
ᐳ27⚓

24ὃ¡¢£ᜓὃ¥ᧇ!ὃ¡£⚪¨©V/i(-1,0),C(0,—3)ᙠy=x?+fcc+c
0=\-b+c-3=cb=-2/•<ஹc--3;.$ᱥḄY᪆y^x2-2x-3.ூ2Y௃᝞
f஺஺ᐵ-.Ḅhi
஺2஺ᐵ-.8஺Ḅhi
ᵫhiḄឋpeqDE=D]E,DF=DF,2/DEFḄᕜD[E+EF+DF,2...>஺IஹEஹFஹ஺2ᙠ1!.D
Ḅᕜᨬ
ᨬḄt•¬y=0,ᑣ-2-2%!3=0YX|=3,x=-1.2.♦•8Ḅᙶ᪗(3,0),;.OB=OC=3,ABOC?Ὺ.BABC.•••8Cᚖ.ᑖ஺3,®஺Ḅᙶ᪗(—2,0),AA(l,-3).a♦;Dஹ஺ᐵ-Xhi
•••4(0,2),,DR=yjCD^+CDf=J25+1=726(25⚓
ᐳ27⚓

25ὃ¡¢£ᜓὃ¥ᧇ!ὃ¡£⚪¨©AQEEᕜḄᨬ¯.ூ3Y௃ᑮx7Ḅ89"
48=4,k\8M,•e,S&AKM~2d.a•:S&AMN=2d>S&ABM=S&AMN
:.BஹNᑮ/஻Ḅ89²?.a,;BஹNᙠḄ12
AM//BN.—3=mf.5cḄY᪆y=Ax+஻z,´"µ”0=3·+mk=1;.¸m=!3.BCḄY᪆¹=x-3,f.AMḄY᪆y=x+n....f.AMḄY᪆y=x+\,y=x+1[x.=-1[x=492°2,YC
-Ly=x-2x-3[j/,=0[%=5
஻Ḅᙶ᪗À4,5Á.•.•Nᙠ8c
.•.fNḄᙶ᪗Àt,/—3Á.஻À4,5Á,NÀf,/-3Á,”x7Ḅ/,Ny7Ḅx7-L
./-0,(26⚓
ᐳ27⚓

26ὃ¡¢£ᜓὃ¥ᧇ!ὃ¡£⚪¨©ᑣ᧕NA/=5&
/N=J«+l)2+(”3)2,MN=_4)2+(t-8)2,;AAMN?ῪABCজ=D
J«+l)2+«_3)2=5q,Y4=1+ᦈ
Z=1-V21.2ঝ/A1=MND
'(1J+("8)2=5É
Ya=6+ᵨ
Z=6-721.2ঞ4N="ND
^(/+1)2+(/-3)2=^(/-4)2+(Z-8)2.Y/=g.ÍNᙠ(!)▲
;.t>3,7,•tḄΗ>1+-\/21>6+5/21':.NḄᙶ᪗ᡈ(1+V2T,—2+J*)ᡈ(6+JÓ,3+JÔ).ூÕ௃Ö⚪ὃ×ØÙÚÛᦪḄឋpÜ)
_`aᦪcÙÚÛᦪY᪆
hiḄឋp
?Ὺ.BABCḄᑨ`Üឋp
xy`ᳮ
!ÚÛᦪḄY᪆
Þ©ßàqá#Y⚪Ḅᐵâ.(27⚓
ᐳ27⚓