苏教版小升初2022-2023学年升学分班测试突破练习（一）有解析

《苏教版小升初2022-2023学年升学分班测试突破练习（一）有解析》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

ூ
ᓣ௃ᦟ᱐2022-2023ᓣᑖẚஹ⚪1.ᑏᦪ஺1_1_4533_33-6)4.஺=3.14x0.8=8.28.0.375=735414_25_57*797=5+8-84.5x9=1.5+4=0.25x4x8=2.ᵨ012345஺814(1)(7.13)x7xi335(2)5.4x5+3.6+3+60%(3)2768-202(4)5.87-(3.14+1.87)3.:2;஺51"-6=6(1),1…=3(2)53“F=8ব(4)3x-0.6=0.9B1⚓/E9⚓

1ஹᓫ⌱⚪4.FᦪḕᶍIJK☢ḄNᦪOKPQR29ISTFᦪU)஺A.2899999999B.2900000000C.29499999995.VWXY⚜[Sᓅ]^_ḄW`U33஺2a4஺஺TḄ`bU)A7C°CB.°C4°3153-4-2-66.19457A.36B.5C.12D.127.cdef
ghi40ᓟk,lheḄmnode᠒62.5%,lheḄmnUᓟk஺A.25B.20C.30D.158.qᐜsᔣᖪvwxfyz{|100ᐗḄ^~ᖪ80y஺qᐜsᖪvᳮ“᝞{Sf{1ᐗSᡃwx4y஺”ᖪvᳮ5S{5%,ᑣᵫRqᐜswxSḄᑭoᩭ100ᐗ஺T~ᖪḄᡂUᐗA.25B.50C.70D.859.¡¢£¤Ḅ¥¦oU32,᝞¡ᨵ180kg,£¤ᨵ)kg.A.72B.108C.120D.27010.ᵨo¨:.ᨵᢇᓄ«S᝞cde¬5ᔴS8cde®¯¬°.᝞fcde¬8ᔴS⌕¬°◤⌕deA.4cB.5cC.2cD.6c11.᝞³S´µ⇪⇩ᑖ¸⌱ºᵬஹ½´ᩩ¿ÀÁAᙢÃᔣBᙢ.☢ÄÅḄUA.ᵬ¿ÀÀ;B.½¿ÀÀ;C.´ᩩ¿ÀḄÀ;᪵D.ÇᨵÈÅz12.
ÉᵨFÊU60ËkḄᙊ┵ÎÏᘤ᯼ÒÓ஺ᯠKSÁᑮÖ×QØQÊḄᙊÙÎÏᘤÚSÛgᙊÙÏᘤÚḄÓÊ|oB2⚓/E9⚓

2A.20ËkB.30ËkC.60ËkD.180Ëk13.ᨵ12ÜÝÞSᐸÚ11Ü᪵àSá᜜Üà¦ãäS᝞ᵨᜩæçSèçéêÈëìíîTÜà¦ãäḄÝÞ஺A.3B.4C.6ஹ⚪14.2.05dm3-ml7.36nP=trpdrrP15.8µïðñò3FïóSEᨵ1Fïóèñôµïð.16.ᵨᙊõöFᕜøU37.68ᔖkḄᙊSᙊõ´úûḄüýU_______ᔖkSᡠöḄTFᙊḄ☢ÿ_________ᔖ2஺17.Ḅ0.3ᔣ50ᙌ.18.rḄᙊḄᕜ.19.Ḅ4ᔖḄ⊤☢"#ᔖ"________$ᔖ.20.ᙊ%Ḅ&☢"'(ᵨ*+⊤,"'(ᵨ*+⊤,-ᙊ┵Ḅ"'(ᵨ*+⊤,o21.ᙊ%/0ᜮ2Ḅ&☢3Ḽᖪ᪗7ᙊ%8☢5cm,920cm஺᝞;<=ᖪ᪗7>?@/ᑣḄcm,Bcm,☢"cm2.22.ᙊ┵Cᙊ%Ḅ8☢"DE"F1G12஺᝞;ᙊ%Ḅ98.4ᔖᙊ┵Ḅ9ᔖ-᝞;ᙊ┵Ḅ98.4ᔖᙊ%Ḅ9_________ᔖ஺ஹᵨ⚪23.HIJK₝ᙢNᨵPQRḄSTᘤSTᘤḄVW12XSYZᜧ☢"Ḅ₝ᙢ\]^;ᵨ_ᦪ⊤,a24./Tb5ᑖB4ᑖ93ᑖ.deT@᎔ᐭ5ᑖḄTbᑁTiZjᑖ\k3⚓/n9⚓

325.T᫜ᑁrḄ8☢"9dm2,wZxyT40.5k.<T᫜Ḅ9Zjᑖ\]}$ᑖTḄ~1k.a26.ᙠ᪗ᨵF1G4000000ḄᙢNᵬᙢD9cm,ᑡCᑡᵬᙢDᔣ2_D⍗ḄF5G4,ḄZj\27._Ḅ}_2ᓟḄ_Ḅ2¡ᙠD18ᓟḄᙢ£¤Z¥D⍗\2g28.§]1a¨©ᩭᵱ¬ᓰnᦪḄ5,®Rᩭ5¯ᵱ¬°ᙠᵱ¬ᓰnᦪḄH,᝕¬ᨵZj¡\29.§]1a¨N³´µᡂ·Ḅᨵ12¡¸¹Ḅᨵ16¡º»Ḅᨵ10¡¼ᨵº»Ḅᨵ2¡.ᔜE¾Ḅ¡ᦪᔜᓰᐰ¨¡ᦪḄÀᑖÁÂ\ᐜÄÅÆᑭᵨ᝞ᡠ,/ᑴÊᡧ/ÌÄ.k4⚓/n9⚓

430.CᑖÍᵬÎDᔣ?£5_@D⍗D⍗@Ïᢥ©3ÑÒÓD196ᓟᐰWḄ5,ᐰWḄ80%஺ᐰWZjᓟ\ÔᐰW◤⌕Zj_\k5⚓/n9⚓

5ᫀ᪆ᑖ1_1_145Ù3_531.3-6Ù64+9=93.14x0.8=2.5128.2128.0.375=073541412552x+=+-=-4.5x9=3.51.5+4=2.250.25x4X8=2.5777758858142.(1)(7-13)x7xl3814=7x7x13-13x13x7=8x13-14x7=104-98=635(2)5.4x5+3.6+3+60%3=(54+3.6)X5+60%3=9x5+60%=5.4+60%=6(3)2768-202=2768-200-2=2568-22=2566(4)5.87-(3.14+1.87)=5.87-1.87-3.14=4-3.14=0.86513.(1)x6=65515áGX6+6=6+6x=l1(2)X+4=3k6⚓/n9⚓

61áGX+4X4=?X44x=353(3)x-12=8235áGX12+12=8+129102424x=+19x=24(4)3x-0.6=0.9áG3x-0.6+0.6=0.9+0.63x=1.53x+3=1.5+3x=0.54.C5.A6.A7.D8.C9.C10.B11.C12.A13.A14.2050-7-36015.316.6-113.0417.94.218.jcr+2r19.96-64k7⚓/n9⚓

7120.S=2ᐔrh]ᡈS=itdh-V=7rr2h-V=3Kr2h21.31.4-20-62822.2.1-33.623.áG3.14x122=3.14x144=452.16
#aäGXSY₝ᙢḄ☢"452.16#஺24.áGåTixᑖ.5x5xx=5x4x3x=60+25x=2.4ᡈ:5ç4*3+
5'5=2.4
ᑖaäGTi24ᑖ஺25.èé40.5+1+9=4.5
dm126.áG9-4000000=36000000]ᔖa;36000000ᔖ=360ᓟ-5+4=9,5360-2x9,5=180x9,=100]ᓟa;äGḄ100ᓟ.27.áG2+2x2=2+4=6]ᓟa18-6=3]_aäG3_ÒÓD⍗஺28.áGᑣRᩭᵱ¬¡ᦪᓰ᝕¬¡ᦪḄG22ë
!□523=5^5,2=3»Rᩭ@ᵱ¬¡ᓰ᝕¬¡ᦪḄG55ì+
IDngq⁐=11^11,k8⚓/n9⚓

85=6.ᡠî᝕¬¡ᦪᨵG525+
6□3-1=56,=30]¡a.äG᝕¬ᨵ30¡.29.áGn¡ᦪG12+16+10+2=40]¡aᓰḄÀᑖFG12-40=30%¸¹ᓰḄÀᑖFG16-40=40%º»ᓰḄÀᑖFG10+40=25%¼ᨵº»ᓰḄÀᑖFG2+40=5%ï᦮ᙊᑖᡂ20ñᡠîᔜE¾ᓰḄñᦪᑖÍGG20x30%=6¸¹:20x40%=8º»G20x25%=5¼ᨵº»G20X5%=1᝞òᡠ,G§¨N³´µᡂ·ᔜEóAᦪᓰᐰ¨¡ᦪôõᡧ/ÌÄ||÷øᨽº»úº»30.áGᐰWG196+
80%+û1ü196ë=490
ᓟaCḄFG—.80%=3,4-------5''D⍗G490x3+4=280
ᓟaG280+5=56
ᓟ/_a490+56=8.75
_aäGᐰW490ᓟÔᐰW◤⌕8.75_.k9⚓/n9⚓