2023年浙江省宁波市重点高考考前模拟数学试题含解析

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2023
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14:.d=2,a„=2n-l.&log2”=(2n-2)log4x=logxn-1(x>0)»22.■.b=xn-'(%>0).nফC"a„a(2n-l)(2n+l)22n-12஻+l)'n+iজ0x=l1T„=(஺+஺2+…+C“)+(4+…+ᒹ)If.1)2(2/z+l)ঝ0XHl1-<11J-"2n+l)1-x'ூ>?௃A⚪CDᦪᑡḄH⚗JKḄLMN⚗OPLQCRS>ὃUVᓄXQYᓄZ[\]^_ឋ⚪a.18.(1)y=ex-4e(2)(5,+oo).(3)-4.ூ᪆௃(1)ᑭᵨfᦪḄghijklᓽn(2)y-I+.0ᙠq4,5rsឤᡂv,w◤f-(a+4)x+3a+4,,0,yiᑮ4{q4,5r(3)(x2-4x+4)e'-a=()ᙠ(0,+8)sᨵ~᪷x)=(f-4x+4)e'-Lfn(X)ᙠ(0,2)sᓫ⌴ᙠ(2,+8)sᓫ⌴ᡠஹ£(0,2),—4%+4-=%£(2,3),஻(<)=a-3)-7,Lm(2)=^஺<07஻(<)Ḅᓽn.ூ௃(1)=ᡠ=+0x=l1/প=-3ej'(D=e,ᡠᑗ¡¢V-(-3e)=e(x-1),ᓽy=ex-4e.

15ফ_f(x)_(x-4)ex-[12_(஻+4)X+3Q+4]g(x)a-x>^(-x)2a¦ᦪ>=§ᙠ¨©[4,5]sᓫ⌴ᡠ“£[4,5],y20ឤᡂv,ᓽX2-(a+4)x+3஻+4,,0,1Qு4o42-(a+4)x4+3«+4<0^,,ᡠ2ᓽ9,&ae(-a),4)U(5,+8),5--(a+4)x5+3a+4<0a>-ᦑ஺>5,ᡠ¯ᦪ஺Ḅ°±²(5,+8).বh(x)=f(x)+g(x)=--------------,h(x)=--------J------xx¦ᦪ³(x)=/(x)+g(x)ᙠ¨©(0,+oo)sᨵ~´᩽±>ᡠ¡¢(x)=0ᙠ(0,+8)sᨵ~C¯᪷ᓽ-4x+4)/-a=0.¶(x)=(x2—4x+4)e*—a,¸!]'(x)=(£-2x)e",ᵫzn(x)>0,x>2,ᡠm(x)ᙠ(0,2)sᓫ⌴ᙠ(2,+a))sᓫ⌴[??7(0)-4-a>0,.ஹᡠ&)_<0M02ஹ^஻=8—”>0,ᡠ&w(2,3),0xw(O,xJQ(¿2+°°)1h(x)>0,ᓫ⌴0xe(᳝,஽)1஻(x)<0஻(x)ᓫ⌴ò᩽±>A1)=(…)=(…"(…+4)e_^%n(x)=(x-3)ex-l(xe(0,2)),ᑣn(x)=(x-2)ex<0,ᡠ஻(x)ᙠ(0,2)sᓫ⌴ᡠ஻(%)

16H(x)=(x-3)/+4x+3(%>0),¸!|(x)=(x-2)e'+4,H(x)=(x-l)e'.0xe(0,l)1H(x)<0M0xe(l,+oo)1H"(x)>0.ᡠ="(l)=-e+4>஺ᡠ"஺)=(^3)/+4Ì+3ᙠ(0,+8)sᓫ⌴ᡠH(x)>H(0)=0,ᓽÍᙠ¼=—£-1Î஻(ᓰ)>¶ᔠ⚪i.ÑÒᩩÔḄ஻?Ḅᨬ±-4.ூ>?௃Ö⚪ὃUfᦪḄ×ᔠØᵨÙ³ᑮfᦪḄghijᑭᵨfᦪẆÛ¦ᦪḄᓫឋஹ᩽±>CKឤᡂvCRS²^⍝Ý⚪.19.(1)—(2)-^3•ூM᪆௃(1)ᑭᵨáâãᳮåæᓄçèᔠéfJKnᓄêæçᐵìKLcosB=,᪷ï3e(O,7r)nLèñ(2)ᑭᵨòâãᳮna2+cஹ2-ac=4ᑭᵨóÖCKnLô%”=4,õᐭ÷çø☢úJKnLèñ.ூûM௃(1)ᵫáâãᳮü2sin3cosB=sinAcosC+sinCcosA=sin(A+C)A+B+C=7r/.sin(A+C)=sinB,&ᔧ£(0,)sinB0z.2cosB=l,ᓽcosB=—2ᵫBe(O,)B=1(2)ᵫᳮ஻2=/+/-2஻ccos5a2-^-c2-ac=4"஺2+C2N2஻C(&'(&஺=c)*+,)-,.4=Q2+/0QCN2ac-ac=acᓽ3)a=4-345☢7SḄᨬᜧ<=-X4sinfi=732ூBC௃E⚪ὃHI345ḄJᐵLM-NOᑮQᳮᓄST4ᐵUVஹᳮI345ஹ345☢7XVYᵨஹ[E\+V]7Ḅᨬᜧ<ஹ^_XVḄYᵨ+LM-`abὃ⚪c.20.(1)dI᪆f(2)ghij.

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