安徽省江淮十校2021-2022学年高三上学期第一次联考文科数学试题（含答案与解析）

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17;EF=—CD=1,AB=1,2:.AB=EFᦑ³Ò;1-Ô³Ò;ᓽBE///F,KLBE0D☢PAD,AFu-☢PAO,BEU-☢PAD.(2)CDḄ¿O,ÎÏPO,BO,PC=PD,ᑣPOLCZ),•.•☢PCD©☢ABC஺☢PCZ)n☢ABCD=CDPOu-☢PCD,POP☢ABCD,å¿Aᑮ-☢PBCḄËÌ1d,ᑣV_=—BeAPBC:.LS4PBc.d=LSUBC-PO,§OBU☢AB஺/.POVOB,BC=BD=0,CD=2,CD06=1,᧕P0=6:.PB=2,PC=2,BC=O,'£P8C=g,⊈°^22_W=W'S"BC=gxlxl=g,.-.lx—xJ=-xlxV3-CD4=ì=íᓽ¿Aᑮ-☢PBCḄËÌ1î.3232ï7722(3ஹ21.ñᙊó=+[=1(஺õ"0)Ḅᯖ¿1£(ª1,0),÷(1,0),í¿71,øᙠE©.b~\2J(1)EḄkú,(2)û׿ḄüjÕ/ý£A4,8V¿ÕþABḄ¿1M
YZ[\Y]^_×Fÿ஻7Ḅ.226ூᫀ௃(1)—+-^—=1:(2)஻2=±——432ூ᪆௃

18ூᑖ᪆௃(1)ᵫᙊḄ!"4=2,#ᵫC=l,$ᔠ஺2=஺2'஺2=3ᓽ!.(2))*+,/Ḅ.᳛0ᔲ2ᙠ45+,/Ḅ.᳛2ᙠ46ᐸ89:y=h+m,;+,<ᙊὶ>,OAOB-OMON^xx+y-m-%AB,ᑭᵨEFᳮᓽ!.t2yi253ூH௃Iপᵫ⚪L!M2a=/ᵨ+|%|=I+]=4,..a=2,Pc=l,V2V2.•.ᡝ="'஺2=34ᙊEḄ89:T+U=1.43(2)জW+,/Ḅ.᳛X2ᙠ4᧕"Z.[-\]=-34ঝW+,/.᳛2ᙠ46ᐸ89:y=-+m,A(XI,yJ,Ww4%)4/ஹ[y=kx+mᑣN(a.ᯠcὶ>d+e_]"(4᝕2+3)V+8/7?u+4m2-12=0,-SkmW-12h஽+%xx,=——s44k2+3'-4k2+3OA-OB-OM-ON=xx+yy-m^^i2i2=xx+(j]+m)(Ax++m+kx+m)x222=(42+1)22:k2(᳝+x)4-mm2/72i\km/

192i\4/-12km-Skm=("+l)xi+o&+%)=(%+1)P<ᓝrᐙ+_-12/+4>-12_-3(4t+3)+4u-346?'3ߟ4k2+3—4t+3—[+4/+3⌕xyz:{ᦪ4}~h◤4,/'3=0,ᓽu=±4᧕M>()ឤᡂ>4h]]—u]=—34ᔠ⚪L.yᡠ4n=.121,22.Mᦪ/(x)=]r-alnx.(1))*/(x)ḄᓫឋA(2)W஺>0,ᐵxḄ89/*)=ᨵ'4஺Ḅ.

20ூᫀ௃(1)ᫀX'4ᐹ᪆A(2)a=`.2ூ᪆௃ூᑖ᪆௃(1)ᦪf\x),ᑖ)*'(X)Ḅ4"ᓫ¡A(2)6g(x)=/(x)-¤4¥ᦪg'(x),ᵫg'(x)=0ᙠ(0,+8)y"x,="+'"'+4","gW22Ḅ᩽«g(G),ᢥg(/)>04g(Z)=04g(>2)<0ᑖ)*g")°j±ᦪ"$*.2ூH௃I(1)ᵫ⚪L4!"²>0h³(x)=x—9=TU^XXজW஺W0,³(µ>0ឤᡂ>4ᑣ/(X)ᙠ(0,+8)y0¶ᦪঝ஺>0,ᑣ³(x)=x'=—XXXᡠ¤5xe(0,G)4/'(x)<0,5xe(«,+8)4f'(x)>0ᑣ/(x)ᙠ(0,ஹG)y0¹ᦪ4ᙠ(ஹº,+8)y0¶ᦪyᡠ4W440,y=/Wᙠ(0,+8)y0¶ᦪWa>(),y=f(x)ᙠ(0,&)y0¹ᦪ4ᙠ(¾,+8)y0¶ᦪ(2)ᵫ⚪L4!"/(x)=//-alnx=ox1,Âg(x)=/(Ã)_^Uoᐗ-a

21x-ax,89/(µ=¤ᨵ'4ᓽ)4=g(x)ᨵ'°jA/ஹaI/?\g(x)=x----a=—[x-ax-a),xxx7Â4஺)=0,"''Æ—஽=o.Ç:஺>0,x>0,ᡠ¤X=ÈÉÊ”.<0(ÌÍ)4"*2+'1225x«04W)4gG)<0,g(x)ᙠ(0,<)0¹ᦪ;5Ï«Ï24+°°)4g'(X)>04g(x)ᙠ54+8)y0¶ᦪ.5X=W,g'(ᵯ)=0,gOOrnin=g(%).Wg(%)>0,ᑣg(X)>0ឤᡂ>4X2ᙠ°j(Ì)Wg(W)=O

22Ö)U°,ᓽ—x^-alnx-ax.=0n9ᑣ2-~!"Ù_21n/=0[g'(²2)=஺-ax-a=026஻஺)=l-21nx-x,Ç:ᙠx>04/i(x)0¹ᦪ4ᡠ¤Úµ=0ÛÜᨵ'.ÝÇ:᱐1)=0,ᡠ¤஽=14ßP"஺=3.Wg(w)1Ç:!<1<஽4gjln'L-^-r-+a-—>0e2e2ee2e2eᡠ¤y=g(x)2ᙠ'±°jA160(x)=ln(x+l)-x,x>0,ᑣ᜛'(x)=-----1=----<0,ᓽe(x)ᙠ(0,+஺)yᓫ⌴¹4ᑣX)I1JCI1᜛(x)<0(O),g|Jln(x+l)-x<0,ln(x+l)—(4a+l)2-a(4a)-a(4a+l)=3a+—>0ᡠ¤y=g(x)ᙠ(஽,4a+I)2ᙠ'±°jAÇy=g(x)2ç±°j(Ì).yᡠ4a--.2ூjè௃é⚪ὃëᵨᦪᦪḄᓫ¡4ὃëᵨᦪẆí89᪷Ḅ±ᦪï⚪4⚪8ðñ89᪷Ḅ±ᦪòᓄ:ᦪ°j±ᦪ4ôõẆíᦪḄᓫឋ4᩽°j±ᦪ