2023届河北省石家庄市数学八上期末联考模拟试题含解析

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2022-2023
ᦪᔁὃ
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108ஹDூᑖ᪆௃ᵫAABDgZ\ACE,AACE^AACM,ABCMêÞ¿¾tújজঝᑨüᵫACᚖ½ᑖEM½¾¿¾ḄឋtjঞᑨüᵫAADMMêÞ¿¾tjটᑨü.ூx'௃',•••ABCMêÞ¿¾.,.AB=AC,ZB=ZBAC=ZACB=60°,VBD=CE,.,.ABDÿACE(SAS).♦.AD=AE,ZBAD=ZCAE,••AEACᢚ.♦.AE=AM,NCAE=NCAM,AAD^AMᦑজ.,.ACE^AACM(SAS)NACE=NACM=60஺ᦑঝᵫḄឋACᚖᑖEM,.".ZCNE=ZCNM=90°,VZACM=60°,/.ZCMN=30°,...ᙠRtACMNCN=-CM,ᓽCM=2CN,ᦑঞ2VZBAD=ZCAE,NCAE=NCAM,.♦.NBAD=NCAM,VZZBAD+ZCAD=60°,ZCAM+ZCAD=60°,ᓽNDAM=60°,XAD=AM.,.ADM"#$%&'•••M4=DWᦑটᡠ*Ḅᨵ4,ᦑ-ᫀ"/D.ூ12௃4⚪ὃ78ᐰ#%&'Ḅᑨ;<ឋஹ#$%&'Ḅᑨ;<ឋஹ&%&'ḄឋஹᚖᑖḄᑨ;<ឋஹḄឋ#>?⚪ḄᐵABᮣDEᵨGHIJ>KLMᳮOP.

119ஹCூ᪆௃KALVABAC=120°,AB^AC.MZBAD=ZCAD=6Q°,BD=CD=-BC=—.24ᙠPZADB90°,ZBAD=60°,.ZB=30°,AD=-AB,BD=—AB,22AAB=2AD=1BD,3.273V31••AB=x—=Q•342ᦑ⌱C.10ஹAூᑖ᪆௃ᐜ᪷TUᑖVḄឋX(YCD=DE,Z[᪷T“HL”Y.RtAACD^RtAAED,ᵫDE%ABPV]DE_LAB,(^AD=BD=3cm,ᯠ`ᙠRtABDEP᪷TḄឋXᓽ(^bBEḄ$.ூc௃defUᑖNBAC]NC=90஺DE_LAB,.,.CD=DE,ᵫAD=AD,ᡠRtAACD^RtAAED,ᡠAC=AE.TE%ABP4/.AC=AE=—AB,2ᡠZB=30°.TDE%ABPV]DE±AB,AAD=BD=3cm,13ADE=-BD=-,22

12ூ12௃4⚪ὃ78&ᑖḄឋᚖᑖḄឋᐰ#%&'Ḅᑨ;RឋS30°&Ḅ&%&'ḄឋTUV;ᳮ#>WXYZᐰ#%&'Ḅᑨ;RឋB?-4⚪ḄᐵA.11,Dூ?᪆௃᪷]⚪^_`a'Qbcd#Ὺ%&'"┦&%&'ᓽM`⚔&Ḅhᦪ"50°.jQbcd#Ὺ%&'"k&%&'ᵫ⚪^ᓽM`⚔&Ḅhᦪ"130°.ூl?௃জ᝞a1,#Ὺ%&'"┦&%&'VBD±AC,ZABD=36°,/.ZA=54°,ᓽ⚔&Ḅhᦪ"54஺.VBD±AC,NDBA=36°,ZBAD=54",AZBAC=126°.ᦑ⌱D.ூ12௃4⚪ὃ78&%&'Ḅឋஹ#Ὺ%&'Ḅឋ,?⚪ḄᐵAᙠoḄ_`a',pᔠa'ᑭᵨᦪ'pᔠstu?.12ஹCூᑖ᪆௃᪷]%&'ḄQ,᜜&#oRwxyzḄ{,ᑁ&Ḅ<ᑡ~ᓽ?.ூl?௃•.•RNABCyzḄ᜜&=NA+NC,.♦.x+65=x-5+x,?x=l.

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15ᑭᵨᖪḄâ·éᑣᙠᵨËḄâ·⌕ñ^òᦪḄ·BᦪËḄâ·éᑣ*TóḄâ·ñ^ᢣᦪyâḄᐵ².17ஹ(x+3)(x-3)ூᑖ᪆௃᪷]Ì~éKLõ~ᑖ?ᓽ.ூl?௃?/X2-9=X2-32=(X+3)(X-3),ᦑ-ᫀ"/(x+3)(x-3).ூ12௃4⚪ὃ7ᵨÌ~éõ~ᑖ?WXYZÌ~éöᮣDᵨB?⚪ḄᐵA.18ஹ1.ூᑖ᪆௃DELAB,᪷]&ḄᑖGḄ1ᑮ&Ḅ{$Ḅ¼½y#ᓽᑮ-ᫀ.ூl?௃?/DE1.ABoE,VBC=10,BD=6,.•.CD=BC-BD=1,VZ1=Z2,NC=90஺DE±AB,.DE=CD=1,ᦑ-ᫀ"/1.ூ12௃4⚪⌕ὃ7&ᑖḄឋ&ᑖGḄ1ᑮ&Ḅ{$Ḅ¼½y#.%ஹ?-⚪(ᐳ78ᑖ)19ஹ(1)180°(2)360°(3)540°ூᑖ᪆௃(1)BC,᝞a1,/ZEBC+ZDCE=ZD+ZE,᪷]#÷ᣚ<%&'ᑁ&<ᓽu?Ø(2)AD,᝞a2,/NEDA+NFAD=NE+NF,᪷]#÷ᣚ<ø$'ᑁ&<ᓽu?Ø(3)CF,᝞a3,/ZDCF+ZEFC=ZE+ZD,᪷]#÷ᣚ<ù$'ᑁ&<ᓽu?.ூl?௃?/(1)BC,᝞a1,/ZEBC+ZDCE=ZD+ZE:.ZA+ZABE+ZACD+ZD+ZE=ZA+ZABE+ZACD+ZEBC+ZDCE=ZA+ZABE+ZEBC+ZACD+ZDCE=ZA+ZABC+ZACE

16=180°(2)ghAD,᝞j2,(kNEDA+NFAD=NE+NF:.NFAB+NB+NC+NCDE+NE+NF=NFAB+NB+NC+NCDE+NEDA+NFAD=ZBAD+ZB+ZC+ZCDAlᑁ&(4-2)X180°=360°,:.ZFAB+ZB+ZC+ZCDE+ZE+ZF=360°ᦑnᫀ%360஺(3)ghCF,᝞j3,(kZDCF+ZEFC=ZE+ZD:.NA+NB+NBCD+ND+NE+NEFG+NG=ZA+ZB+ZBCD+ZDCF+ZEFC+ZEFG+ZG=NA+NB+NBCF+NCFG+NGpᑁ&:(5-2)X180°=540°,NA+NB+NBCD+ND+NE+NEFG+NG=540஺ᦑnᫀ%540°ூ45௃7⚪ὃ;rᑁ&⚪Ḅᐵs᪷T⚪PtbḄuvᵨxyᣚ{⌕^Ḅ|ᓄᙠ~*rᑁ᪷TrḄᑁ&^ᓽ(.20ஹ(1)160(2)=0.3,n=O.l;(3)nᫀ᪆.ூᑖ᪆௃(1)᪷TCᦪxᐸḄ⚣᳛ᑡᓽ(n(2)ᵨᦪ+AḄ⚣ᦪᓽ(Ḅm,ᵨᦪ+DḄ⚣ᦪᓽ(Ḅm(2)ᦪᑖBஹDḄ⚣᳛^ᐸeᦪᯠ`⊡ᐰjᓽ(.ூc௃(1)32+0.2=160(),ᡠ7;Ḅᦪx%160(2)=48+160=0.3,/?=1-(0.3+0.35+0.2+0.05)=0.1

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