2021-2022学年北京市某中学高考物理押题试卷含解析

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2021-2022
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13d9.80x10-3V=—=m/s=1.63m/s%t6.0x10-3বᑣᨵ:v2=2.66m2/s2(3)[4]ᐜ᪷øù⊤ÂḄᦪûü®ý<Þv2-cosOþ᝞:(4)মᵫv2-cosO᳛Ḅ:,10-0”k------------=201.0-0.5⌕ឤ!"#:12mg(l-IcosQ)=,mvᓄ%᦮ᳮ(v2=2g/-2g/cos0ᑣᨵ:2gl=k=20+:I-1.0m12ஹ(1)BC(2)Aூ+᪆௃(1)34567ᘤḄ9:ᙌ<=ᙠ?@ᵯBCDEF⍝9ஹH:ᙌḄᵯ7IJ:ᙌKᦪIMNḄᐵP,R◤⌕ᵯ7⊤஺ᦑWXᵯBJᵯ7⊤YZᘤᩞ\]^⌱BCD(2)জᳮc67ᘤ9ஹH:ᙌᵯ7JKᦪḄᐵPd=dDf67ᘤḄ9:ᙌ=“0D8”=:kH:ᙌ=:“0D4”=:kᑣ9ஹH:ᙌKᦪId=D=2,ᑣ9:ᙌYmᵯ7n=dnD=2x5V=10V஺ঝ3⚪5t67ᘤuvᳮ

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16y3xḼXz{|ᔣ⌮┐ᑮXz|ᔣḄᙳᡭᙠyzCᦑᡭᙠyzCḄᓰᡠᨵᦪḄ50%.14ஹ(l)v=8m/s,v,=4m/sD(2)v=2m/s,”=4D(3).v-3.9m,s=4.Imo2Bcூ+᪆௃(1)ᙽḄᑖvo,n.4ᵫឤE=~mAvl®P+v=8m/sঝ0ABXᐰvឋᵫឤ(¡%=(£+¥)ᵞঞ+Vi=4m/sটফᨬ«ᙽ஺ᐳᙳᵫឤ(m+m)v+ᱨ+mc)v2ঠA/il+v=2m/sড2ᙽ஺Ḅ¯°±²s,ᵫឤ³/gs=1(m+m)vD-g(%+rn+)µঢABB+s=4mণ

17CḄ¸¹º»ᦪ஻ᑣᨵs-dn=------+1ত2L+n=4.25½n=4থ(3)JᙽA¾ᜧÀa”ᙽCḄ¾ᜧÀÁ,ᵫÂÃÄn஻¾eg=(஻%+%)4+q=lm/s2a=lm/s22(Åᙽ4)JᙽCḄƯÇXឋÈᣚᨬ«ÊᐳËᓃ=2m/sÍΰ஺ÏᑮÍΰḄN,,ᑣÐ+Z=2s+d+3LÑᐭᦪÓḄs=3.9mধBᙽCḄÔÕ

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