2023年甘肃省徽县高考冲刺试题（最后一卷）数学试卷含解析

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2023
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Ḅß½od,ᑣd>0,ᵫ:êஹ4ஹíîᡂ@ᦪᑡᑣᓽï஺2+4஻ð2=4ï4+1°஻ð,a,-,+10J1849;d>஺,WXa,=84,ñò•=1--------=GV=u.aaAsa4229ᦑ¢ᫀou—.4ூwx௃z⚪ὃ|@½ᦪᑡÐ⚗ßA)@}⚗Ḅ²ᵨὃ|ôõ¦:§Ạ⚪.öஹW¢⚪uᐳ70ᑖ஺W¢²ᑏ±ᦻùúûஹüûÑýᡈþÿ஺17.᪆ூ᪆௃⌱জ6=A=27sinC=W,᪷ᳮᑮ஺=3,☢ᑮᫀ;⌱ঝa=6,434bfᦑB>A,A!"#ᦑ%&⌱ঞa=36sinB᪷ᳮsinB=(sinC=Y^),24᪷ᳮᑮa=3,☢ᑮᫀ.ூ+௃⌱জB=—,A=^-7r,ᦑsinC=sin,A+B-=sinAcosB+cosAsin8=./(.43''4᪷ᳮ-,ᦑa=3,ᦑ5=,஺12஺=ᓃ4.sinAsin624⌱ঝci=5/39b=^6,ᦑ5>A,A!"#ᦑ%.,3FsinBGab_____________⌱ঞa=30sinB᪷ᳮ55=/6ᦑG-sinB»sinAsmB—2sin8sinC=sinA+B-=sinAcos8+cosAsinB=------.

12᪷ᳮ7/=2,ᦑa=3,ᦑ5=4=.1)஺=9-36.sinAsinB24ூDE௃F⚪ὃIJK#ឤMNᣚᳮ☢PQRᙠὃITUḄWXYZᔠ\ᵨWX.18.(1)ᫀ`a/ᐹc᪆(2)de᪆(3)de᪆ூ᪆௃(1)fgg(X)Ḅjklmᦪopᦪ஺ஹ஺ᑖstuᑮᫀ.(2)vmᦪMx)=/(x)-(3x+l),fl|emᦪḄᓫ~ឋfgmᦪḄᨬᜧᓽd.(3)ᵫ(1)xNl+lnx,nr#(x+l)2esinA>1+ln[(x+1)2esinv],ᓽ(+1)2/2221n(x+l)+sinx+l(x2+2x+2)esin">(x+l)2esin'ᓽd.ூ+௃প:8(*)Ḅjk!(0,+஺)g,(x)=aXb,a>0,6<0g'(x)>0,ᑣg(x)ᙠ(0,+X)ᓫ~⌴&a>0,X>0g'(x)>0,x>£,g'(x)<0,00g'(x)<0,ᑣg(x)ᙠ(0,+஺)ᓫ~⌴¡&"0,b<0g'(x)>0,02,ᑣg(x)ᙠ(0,£ᓫ~⌴ᙠ12,+8aa\aJ\aᓫ~⌴¡&ஹஹ/2(2)devmᦪ஻(x)=/(x)-(3x+l),ᑣ஻(x)=——-+cosx-3.2¨!xNO,ᡠ«----£(0,2],cosxe[-l,l],x+1ᑣ஻'(x)wo,1஻(X)ᙠ®0,+8)ᓫ~⌴¡ᡠ«/2(X)=/(X)-(3X+1)

13ᵫ(1)g(x),N=g(l)=O,ᡠ«g(x)=x-l—InxNO,nᓽx21+lnx.x>—1(x+l)2>0,(%+l)2esinx>0,ᑣ(x+1)2⁐">l+ln[(x+1)2esinv],ᓽ(x+l)2esm221n(x+l)+sinx+l,(´2+2%+2µ'>(&1+1)2¶”,ᡠ«(x?+2x+2)e'in*>21n(x+l)+sinx+l,ᓽ/(x)<(x2+2x+2)esfூDE௃F⚪ὃIᑭᵨlᦪẆº»pmᦪḄᓫ~ឋᑭᵨlᦪde`MQ¼½¾⚪.19.(1)ᫀ᪆.(2)ᫀ᪆ூ᪆௃(1)ᑭᵨÀF`MQÁ+ố2a,U+a2b,ÃQÄÅᓽf.baÆ2ஹ»2/ix(2)ᵫ(1)42.7a+h--^ab+—■,Êᐭ`MQᑭᵨÀF`MQᓽf.(aJaூ+௃2T2(1)—+b^.a,—+a2bbaÃQÄÅZ+Ï..4+8abb2\b\a-^ab+(2)ᵫ(1)Ð..6---a)aᓝÒ2஺1,b2(a-b)a1½ÓQ—r--------..ah+-H—---T---------------------/?a(a-b)Õ+=]+Öa1)H--------IXJIaa(a—b),.஺J..2—+2—>4.ba

14ூDE௃F⚪ὃIJÀF`MQḄ\ᵨ¼½ÀẠ⚪.20.(1)de᪆(2)-ÁN35ூ᪆௃(1)Ù45ÚD!஺ÛÜOC,஺ÞAC,4ᨴ᪷àáᐵãdeAABC!MåK#æᓽ43_LOC&ᵫᵨ!MåK#æ1ᵫà☢ᚖêᑨìᳮdeA3,í☢஺ὡc,ᓽdeA3,8c.(2)«஺!ïD஺4OB,0c!x,zñòóôõê#ᙶ᪗ãᑏgᔜúDḄᙶ᪗ûfí☢88cYí☢BQḄüᔣþᓽᵫüᔣþüf5☢#D-B,C-BḄÿ
.ூ௃(1)A3஺OC,஺AC,᝞ᡠAD=1,CD=I,ZADC=90°,ᡠ(AC=2,ᦑAABC,-./0ᑣABLOC.ᐭὡ=2,ZABB,=60°,ᡠ(A4B7,-./0ᑣABI஺4.90஺0஺4=0,ᡠ(AB,:☢஺4C.gCu:☢ᡠ(ABLgC.(2)ᵫ(1)?:☢ABC஺@:☢A65A=AB,OCu:☢ABCD,]ᡠ(OC,:☢AB84(஺C஺OB,OCx,y,zEFG᝞ᡠḄIJK/ᙶ᪗N,

15᧕OC=OB]=Cᑣ3(0,1,0),4(G,0,0),C(O,O,G),DI22JᑣP=(0,7,6),^C=(-5/3,0,73),CD=U:☢BBCḄVᔣX஻[=(X],y”zJ,RC=0,_%+6g0,ᑣீb____ᓽh᳝=1,jkIy=6Z]=1,n1•B]C=0,—y]3X\+<3Z\=0,ᦑ)=(L6R.U:☢800ḄVᔣXl=(w%Z2)___3ᑣீn%•CoD=0p,ᑣ—2y72---2-222=0,[஻2ᵫ஺=0,[_q+r/0,hs2=1,ᑣt2=-uZ=\,ᦑ஻2=1bv123,ᵫw?p☢/஺bx஺b5yp☢//,ᡠ(p☢/D-gC-8Ḅz
bᜐn.35ூ|௃}⚪ὃ☢ᚖKḄᑨᵫ☢ᚖKᑨᚖKᵫIJᔣXV:☢:☢0ᡂp☢/Ḅᜧ᫏⚪.21.(1)/(x)=-In%(2)᪆.ூ᪆௃

16(1)᪷⚪/(X)ᙠ(0,ᵪ)nᓫ⌴/'஺)=2࠷-=3(>0),ᑖ£¤¥/(X)ḄᓫឋXX§ᔠ⚪©“X)Ḅ᪆«1,I,1(2)ᵫ¬x,Pb=/(%)+mḄ®¯°᪷©In᳝+±=஻z,InX2+±=²®«³ᑖ´µ©¶·x,,2x¸2ᑭᵨᣚᐗVh=n·᪀⌼¿ᦪ=᪷ᦪẆÂᓫឋ©஻(“<஻(1)=0,ᓽw©஽t§¥.ூ௃(1)᪷⚪/(X)År®¯Æ,ḄÇ°ᦪ᳝ᮞÉᨵ\•/<()ឤᡂG.x—xA2ᑣf(x)ᙠ(0,+8)nᓫ⌴/'(x)=2ax--=2*%>0),XXÐ4=0Ñ/'Ò)<0,7(Óᙠ(஺,+8)ᑁᓫ⌴.Ða>()Ñᵫf'{x)-0,ᨵx=-——,<2a×ÑÐ1°ᔡ)Ñf(x)<0/(x)ᓫ⌴Ðxe(Ú,+<»)Ñ/'(Ü)>0,/0)ᓫ⌴ÝÞna=0,ᡠ(/(x)=ßlnx.(2)ᵫá,ᓃPã-=/()+äḄ®¯°᪷2x,1,11nxl+——=m,Inx+=m,212x2Xx2®«³wlnX|Tn/+ç--=஺2x2X}2A-l1_è,XX.7×XéOP---=---------,21nê21nêxx22

17h1=ëᵫ&<஽012In/ᦑX]+ò>1,ó⚪.ூ|௃}⚪ὃᑭᵨᦪẆ¿ᦪḄᓫឋ¿ᦪḄ᪆«ஹ(õᑭᵨ᪀⌼¿ᦪVÆ,«ὃöᓄøùஹ⚪ᑖ᪆úû·üµúû.-7ஹ1622.(1)-,+oc(2)—[3)9ூ᪆௃(1)ᑭᵨýᑖþVÆ,«Ḅÿ.1Q(2)ᐜ(x)5,ᓽ2஺+3஺=5(஺>0>0),᪷“1Ḅᣚ”Ḅᔠ-----+-—Ḅᨬ"#.ூ%&௃3(1)(x<—2),—X—2—x+3W3x—2,ᓽx2+,&-77()x+2-x+3<3%-2,ᓽ./0.Kx«3-33(x>3)x+2+x-3431.2,ᓽxNl,x>3.ᦑᡠḄ&34g+8)(2)54f(x)=|x+2|+|x-36(x+2)-(x-3)|=5,ᡠ62஺+3஻=5(a>0,b>0),8!J2஺+1+3(+1)=9,

18L+öö+÷[2«+l+3(Z?+l)]=110+3(஻+1)+3(2Q+1)2a+1Z?+1912஺+1Z?+12஺+1஻+12a+1=/7+1,øùø<2a+3ᓃ=5,ûüý.a>Q,b>Q,b=-4ḄᨬA9.ᦑ——ÿ+=72Q+1஻+1ூ௃⚪⌕ὃᑖὃᑭᵨᨬὃᓄ!"#ᓄḄᦪ&'()*+,᫏⚪.