2023广东高考化学模拟试题及答案

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/mJLVHHO/mLpH42I20005.28II20185.78III2a165.78IV21085.78জ⊡ᐙ⊤*ᦪÐ@Oঝᵫ×ØI¬nÙÚÛNH4clHÜ“ÝÞ”ᡈ"ᢓᑴ”NH@0§kᔠ⊤*ᦪÐâãᑨåᳮᵫ@ঞkᔠ⊤*ᦪÐᑖ᪆cHCléᜧNH@0§HÜ“éᜧ”ஹ“êÅ”ᡈ“ë”஺টíãÛ0.05mol/LNHNH4clîpHïᐭ0Ḅëᓄñòn᪗ôãpHḄëᓄö஺18.H14ᑖ÷HScMùúᨵûü஺ýþÿ
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¼½XVW#M¶·ḄBC®9r஺(7)¾¿J#À3ScÁᑖÂᙠÃrÄBCḄÅᦪ¹lgc(F)»ஹpHḄᐵ᝞;ᡠ=஺“ÈpH”¤9ÉᑴpH=7,¡“V"”¤9PQc(F)Ëᑮ5x10-mol/L,ᑣ+33ScḄÂᙠÃr(ᓄr#?@ᔞ5=0.7)஺1-/Sc(OH),SC(OH)COXNOÑ~ᨵÒ¼½#ÓÔḄẆÖ⊤×#ØÙÑ~
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ᳮßᵨ#à~á▤ã¾äḄ¼½஺dJᑡf⚪>প2NO(g)+2H2(g)UN(g)+2HO(g)A/f=-664kJ/mol~ὶᔠê⏚1222ëìíîᱥ᣸ïḄ0⌕஺MᑖÀ¶Yᡂ(Ñ~ðᑖC#ᓽᱥÑòᨵ´6ᑖC)#ó´¶᝞J>ô1¶>2NO(g)^NO(g)A/7=-103kJ/mol22ô2¶>NO(g)+H(g)NO(g)+HO(g)A^=-17kJ/mol22222জᑏiô3¶Ḅöᓄ®9r>oঝjᐗ,"A(g)+஻B(g)=஻C(g)+qD(g),úû᳛ü=Ac"'(A),c"(B)஺2NO(g)+2H2(g)=N(g)+2HO(g)Ḅúû᳛þ=ÿ•c2(NO)᳛22

7V=(I—*')a⊝ᓄ᳛/ᓄ᳛kஹk]ஹ%ᙳ᳛ta)ᦪ!"#$!"ᓣ&᳛ᦪ'ᜧ஺L+ᩖᑖ./0123᳛Ḅᨬ(6“8”ᡈ“᠒”Ḅᐗ@AᓄBᨬ&Ḅ

8(1)ᓄᔠᱥBḄᓄ×ØÙo(2)IḄÚÛᱥCeHioOÝÞßᓄᔠᱥà᪶âᐳäåæçYè☢êë2`2`I,ìÚḄᓄ×ígîo(3)n@SnCðᓄᑺᑣìḄßò஺(4)E᧕õö^_o(5)◀H᜜ᓄᔠᱥLḄᓫHOOCNH(CH2)6NHCOOHr(6ü᪀þî)஺(6)᪷ᓄᔠᱥGḄ᪀ᱯᑖ᪆⚜ᐸḄᓄឋὃজḄᡂ⊤஺᪀ᱯ!"Ḅ#$%ᑺ!"'ᡂḄ(᪀জ-NHHC1-NH,Cf2ঝ———ঞ———030(7)ὃ23456789:;⌕=ᧇᔠᡂ஺?஺Ḅ@A⊡ᐙᐰ(EᵨGH!"ᩩJ)஺1.A2.B3.B4.C5.C6.D7.C8.C9.D10.A11.B12.A13.A14.AI5.D16.CZஹ\⌱^⚪17.`14ᑖa`1aজ8`1ᑖaঝ3ᓉ“xl`a7Qᑖa`2a©NH,+HO^NHHO+H+`2ᑖᱥ1ᑖ⌮n1ᑖa2r2

9ঝ5.5x10-1஺ঝᑖa`3aজ2`1ᑖaঝop`1ᑖa᝞rNH,stEuvwxy10zpH"|5.28}~ᑮ6.28,᪷⊤ᦪpH:5.78,ᓽC`H+astEuvwᜧᡠ7xyopst`2ᑖ=ᳮᑖ᪆EᑖaঞE`1ᑖaHd£爱妲ট~ᐭsḄ/mLQᑖA1ᑖᓄ[5.28.7a1ᑖ஺ᙶ᪗ᣚ¢£ᓄ¤¥¦a஺18.`14ᑖaপIs22522P63s23P63dzs2ᡈ[Ar]3dzs2`iᑖa`2aᱥA`1ᑖa¯s`2ᑖa`3a1.8`1.7ᑮ1.9ᙳ2ᑖa`4aNaOH+Sc`OHa=Na[Sc`OHa]`2ᑖa34`5a■¶Fe+¹TiO?+ᙠ“st”¾¿ÀÁÂEᑭÄᐗÆTiÇFeḄᑖÈ`2ᑖa`6aAl3++Fe3++஻SOj+`6-2naHCO,=AlFe`OHa_`SOaJ+`6-2H
COT62n4,a2`2ᑖa`7as%`2ᑖa19.`14ᑖaপজN2`a`ga+%`ga=M`ga+Ñ0ÒaAH=-544kJ/mol`2ᑖ“==”¦ÕᑖaঝI.᠒`1ᑖa1`2ᑖaII.×`1ᑖaØÙᓣÛk2}ᜧa×ÜÄ490°cÀ஺᝕2}ᜧᓰ;à!"á᳛~ãÛÄ490°CÀa×ᓰ;à!"á᳛ä᠒`2ᑖa`2aজABC`2ᑖaঝE`1ᑖa᪷Kp|=q=1.00è%,+%=1200kPa,ᑖéGoP=P=600kPa,ᓽC2CO&2=P=600kPa`3ᑖaC020.`14ᑖa`1aêë⏣`1ᑖa

10()(3)íî!"(1ᑖ)(4)EᑖðḄñòÇsᑖðó'ᡂᑖðóôõ(2ᑖ)(5)HO(CH,),OH(1ᑖ)(6)ঝöHC=CH—-H20cH2-(2ᑖ,ø┯1ýᡷ1ᑖÿᫀᔠᳮᓽ)ঞöOHNaOH-ONa(2ᑖø┯1ᡷ1ᑖᫀᔠᳮᓽ)(0HHQ0Hú[HOᗟCOOHOH°ü°]H2C=CH2^^OHfCHOi^0°HoA?(7)(3ᑖᐸᔠᳮᫀᑖ)