2021年福建高考质检化学试题附答案

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20215ᨴᓄ⚪ᑖ100ᑖὃ75ᑖH1C12N14O16Na23Cl35.5ஹ⌱⚪(⚪4ᑖᐳ40ᑖ஺⚪ᙳ#ᨵ%⌱⚗'ᔠ⚪))1.,-ᧇᵯ012ᢗ410056789:;ᓄ<᣸45.1>ᔴ@A᩽ᜧDEr(Y)>r(Z)>r(X)C.ÓᓫÕ᝱,ᓄᱥḄ×ឋØW>YLi+<7D.XḄᨬÙ;ᓄᱥ²~ᓄᱥḄ⏚ឋᜧ£Z/-Zஹ5.Li-FeSzÚÛ¡ᵯ0ÜᵨuÝmᓄÞßḄÞàᵯáᙠlᦈᑮäp./åæçᜮæ-é-ᩩÚᱏìí±²4ÚbLiCI-KCIᰚᓄ§Û¡ᵯ0஺LᑡᨵᐵLi-FeSzÚÛ¡ᵯ0ḄOPvwḄTA.ïᵯ0dmᙠÜðLbᵨB.4ᵯᵯ0Fᵯ·ḄAñC.FeSᵯ᩽òv᩽ᵯ᩽±²oFeSz+2eó=Fe+2S2D.4ᵯᵯ0ᑁõLi'ᔣLiᵯ᩽öp6.÷øùúûTgf÷⏚Ḅüýþÿᱥ
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+CO1+HO3228.ᧇ¤¥H¦|⏚[NOBᓄᡂNO,¨{|⏚©BᓄNOª«BᓄAᔾᦈNCX¯©ᔾ2ᦈNO஺°±²³´µ¶·¸¦ஹ{|⏚BᓄឋḄº»¼½
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*îïᐰᳫÔ᎛ñᓄḄᐵòóᑴê⁚஺"¿ÍæçèéêḄõᓫ÷ᳮ¿஺"ᑡ&'┯)Ḅ*A.æçèéê8s[ø□úᓄÍᓄ±B.┛ᓄüýCOzḄ3qrstH2HC5-+Ca2+=CaCO1+CO1+HO322C.Ḅ⌕ᨵḄ⏚ឋஹஹᱥḄᑖ#$D.ᐝᔠ(ᵨ*+ᡂO.lmol0CH,஺3,45ᵯ7ᦪ94M0M⊤=>?@ABCᦪ310.CE*ᔣ0.1moM/iNNHCChKL⌲NOᐭNaOHKLQRឮTUC,KLQNH/ஹNH3H2஺ஹHCO3XO2Ḅᑖ#᝞X0YᶍKL[\Ḅ]ᓄ3஺_`CEa0NH3-H2O=L8X10-5,%IH2CO3=4.23xlO-7,MHCO3=5.6X10-11,ᑣEᑡghijḄk2

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10.5%NaCIONaOH
75%ᵨ⏀ᔲ᝞1
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4Ôsc(H)/molL-1c(NO)/molL-1Ð᳛2T10.10.1VTi0.30.13vTi0.20.28vᑣÐ᳛`$a=_P=_o(4)Õឋ×ᜐᳮ¦§¨©$NOḄ¶C(s)+2NO(g)=^M(g)+CQz(g)/0஺ᙠឤÙrÚÛᘤ$yᐭÜḄÕឋ×ÇnḄNO©YZ[ÍÇnÝᑮß⊝á᝱ḄDoA.MNz)=k(CO2)B.Ûᘤ᜜ä%åkÃæᣚC.Ûᘤᑁ©ḄᱥCḄ%:D.Ûᘤᑁ©rs%:ম¯ẆêᕒÇìẆmᙠC(s)+2NO(g)$Õឋ×íî┛ஹ┲JᓄᱥḄÕឋTU஺ᙠñòᘤ$ᑖóyᐭCஹCaO/CஹLazOJC,ôᐭNO(ᐸösÝᑮ0.1mo÷L7஺%µÔsab2ù99NQ?◀᳛᝞Ëᡠa-o-CaO/Cbf-La,O,/Cc-O-c(490,45)01-Q-------1------*----1τ20030040050060070017CজúËᑖ᪆490஺(2YÕᓄᨬùḄD(ᵨaஹbஹc⊤)஺ঝ4900C9ḄÐ᳛KNO)=mol-L-1^1ঞþÿ
Ḅ⊝ᦪ100,ᑣᑮ⊝NOḄ◀᳛(ᶇᨵᦔᦪ)஺14.(10ᑖ)!"#$%ᓄ'()ᨬ+⌕Ḅ-ᑺ஺(1)/0ᑁ23ᨬᜧḄ56ᐗ8%CaஹK:56ᐗ8%0ஹC;<=ᐗ8>?ᵯABᵫDᑮEoḄFG%஺ᨔI-J#KL%஺(2)ᔠN⏚PQ(FeSQr7H2஺)RSTU#ᐸWᑁXWYAZ[ᵯZ\]⍝⊤`abcAZde☢0᪀h#ᑣcᔠᱥ᜜XᑖZᦪO(3)lmnḄoᨔ0pqᓝe=#ᐸWo-VIIḄᨔ0s᪀᝞uᡠ`஺wo-VIIᨔ0Wxyyz({KZ᪶}~)apm,ᦪM,ᑣo-VIIḄᨔ0
-3gemo15.(10ᑖ)ᵬ⏚ᵬ##SPMMA,RSᨵᴻ஺ᵨᵬᔠᡂPMMA,q᝞

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6¸ὃºᫀ¼½ᑖ᪗¿?ஹ⌱®⚪°±²⚪4ᑖ#ᐳ40ᑖ஺±²⚪ᙳªᨵ?¥⌱⚗µᔠ⚪¶·⚪G12345678910ºᫀCCAABDBADBÀஹÁÂ⚪5²⚪#ᐳ60ᑖ·11.14ᑖ·পÄÅÆ1ᑖ·22Br-+Cb=Brz+2CÇ2ᑖ·AC2ᑖ·বCaSd2ᑖ·ভqÉ1ᑖ·MgCb2ᑖ·ম2H++2e-=H2Tᡈ2%஺+2e-=%T+20HÌᑖ6BCD2ᑖ·12.14ᑖ·1100mLÍ3ÎஹᡲÐᜩ2ᑖ·2জCI21ᑖ·{ᓄ1ᑖ·ঝ()IWÓÔỚᓄÖ×ØÙÚÛÜ⁐Ḅ}Þß#àáâ⏣äNaCIOåKCb2ᑖ·°wªà“ÓÔỚᓄÖÙÚ”èéᑖ·ঞNaOH2ᑖ·বজìíỚᓫïᓣñ1ᑖ·CIO-+2r+2H+=Cr+l2+HO2ᑖ·2ঝò⁐1ᑖ·1.10%2ᑖ·13.12ᑖ·14NHg+6NOg=5Ng+6HOIH=-1806kJ-Lmol2ᑖ·32224NH+4NO+O=4N+6HO2ᑖ·3222312ᔜ1ᑖ·4BD2ᑖ·5জa1ᑖ·ঝ0.02251ᑖ·ঞ95%94%~96%ᙳô·2ᑖ·14.10ᑖ·1஺CCaK2ᑖ·ᨔ%À{ᓄấᨔ0#6KZᨔ0஺KZᨔ0ᑁᡠᨵKZö÷qᐳ[yøù#I-J஺2ᑖ·ú|T|T|T|H23d62ᑖ·12ᑖ·27X73X1O3032A4kXa32ᑖ·15.10ᑖ·1ᵬü2ᑖ·ýýþyஹÿ2ᑖCHa.CH3Iᓄᑺ4I21ᑖCH2=CCOOH+CH3OH---------->CH2=CCOOCH3+H2O3ᑖ3CH32CCHO2ᔠᳮᫀ2ᑖ

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জ◀Ḅ5"#$%&'()*+᡾-ঝ◀Ḅ/஺2"#$%&'()*+᡾-ঞ12345᳛஺"789:ᫀᡈᐸ>ᔠᳮ:ᫀᙳB2ᑖ2ᑖ5
CDEFGHFe3+JI34KᐙᑖMCDEFNHNOḄPḄᓄ஺:1Qᡈᐸ>ᔠᳮ:ᫀᙳB2ᑖ2ᑖ56aVxlg-3x6
100%2ᑖ0J10007
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SiO2ᑖ22
TFe2O3UAIVᓄᡂXYZ1ᑖ-ᢓᑴZQ2+Ḅ]1ᑖ3
জ6,3x10-24.8஺2ᑖ@2ZrOCI+NaOH+3HPO=NaZrPO34/+3HO+4HCI2ᑖ234242ᡈ2ZrOCI-8HO+NaOH+3H3Po4=NaZRPCUbJ+19H2஺+4HCI224
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-122.542ᑖ2
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104
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9CO+4AI3++12e=2AICO3+3C2ᑖ2236
Al2CO33*]ᡈU]342ᑖ14.10ᑖ1
TiGeSe2ᑖᑏ$8e2ᑖᑏ$1ᡈ2e1ᑖ஺2
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